Question

我需要使用sax解析器从下面的xml中将所有xml元素（在特定元素下）作为字符串。

示例xml：

<root>
  <meta>
    <elememtA>xx</elememtA>
  </meta>
 <payload>
    <parent>
        <child1>a</child1>
   </parent>
   <parent>
        <child1>b</child1>
   </parent>
  </payload>
</root>

Sax解析器实现：

public class UserHandler extends DefaultHandler {  
    @Override
    public void startElement(String uri, 
    String localName, String qName, Attributes attributes)
    throws SAXException {
    if (qName.equalsIgnoreCase("payload")) {
    //need all elements inside payload as string
}

例如，

我需要快速输出：

<parent><child1>a</child1></parent><parent><child2>b</child2></parent>

Answer 1

这是工作代码。你可以在输出的底线看到你的结果。享受。

<强>输出

2017-06-14 09:43:49 DEBUG SaxTest:94 - start document
2017-06-14 09:43:49 DEBUG SaxTest:107 - START -  - parent
2017-06-14 09:43:49 DEBUG SaxTest:107 - START -  - child1
2017-06-14 09:43:49 DEBUG SaxTest:33 - STRING : a
2017-06-14 09:43:49 DEBUG SaxTest:52 - END -  - child1
2017-06-14 09:43:49 DEBUG SaxTest:52 - END -  - parent
2017-06-14 09:43:49 DEBUG SaxTest:107 - START -  - parent
2017-06-14 09:43:49 DEBUG SaxTest:107 - START -  - child1
2017-06-14 09:43:49 DEBUG SaxTest:33 - STRING : b
2017-06-14 09:43:49 DEBUG SaxTest:52 - END -  - child1
2017-06-14 09:43:49 DEBUG SaxTest:52 - END -  - parent
2017-06-14 09:43:49 DEBUG SaxTest:41 - end document
2017-06-14 09:43:49 INFO  SaxTest:148 - RESULT 
<parent><child1>a</child1></parent><parent><child1>b</child1></parent>

Junit中的代码 - 使用工作测试

package com.rizze.beans.labs.sof;

import java.io.IOException;
import java.io.StringReader;

import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParserFactory;

import org.junit.Test;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.xml.sax.Attributes;
import org.xml.sax.ContentHandler;
import org.xml.sax.InputSource;
import org.xml.sax.Locator;
import org.xml.sax.SAXException;
import org.xml.sax.XMLReader;

public class SaxTest {

    public static Logger logger = LoggerFactory.getLogger(SaxTest.class);


    public class SaxProcess implements ContentHandler {

        private boolean start= false;
        private static final String START_ITEM = "payload";
        private String result = "";

        @Override
        public void characters(char[] ch, int begin, int length) throws SAXException {
            if(start == true){
                logger.debug("STRING : "+new String(ch).substring(begin,begin+length));

                result+=new String(new String(ch).substring(begin,begin+length));
            }
        }

        @Override
        public void endDocument() throws SAXException {
                        logger.debug("end document");
        }

        @Override
        public void endElement(String uri, String localName, String name) throws SAXException {

            if(name!=null && name.compareToIgnoreCase(START_ITEM)==0){
                start = false;
            }
            else{
                if(start == true){
                    logger.debug("END - "+ localName + " - " + name);
                    result+="</"+name+">";
                }
            }


        }

        @Override
        public void endPrefixMapping(String prefix) throws SAXException {



        }

        @Override
        public void ignorableWhitespace(char[] ch, int start, int length) throws SAXException {

        }

        @Override
        public void processingInstruction(String target, String data) throws SAXException {


        }

        @Override
        public void setDocumentLocator(Locator locator) {

        }

        @Override
        public void skippedEntity(String name) throws SAXException {


        }

        @Override
        public void startDocument() throws SAXException {
            start=false;
            result = "";

            logger.debug("start document");
        }

        @Override
        public void startElement(String uri, String localName, String name, Attributes atts) throws SAXException {

            if(name!=null && name.compareToIgnoreCase(START_ITEM)==0){
                start = true;
            }
            else{

                if(start == true){
                    //if already started ... go on
                    logger.debug("START - "+ localName + " - " + name);
                    result+="<"+name+">";
                }
            }


        }

        @Override
        public void startPrefixMapping(String prefix, String uri) throws SAXException {


        }

        /**
         * return resulting string
         * @return
         */
        public String getResult(){
            return result;
        }

    }





    @Test
    public void test() {


        String xml = "<root><meta><elememtA>xx</elememtA></meta><payload><parent><child1>a</child1></parent><parent><child1>b</child1></parent></payload></root>";
        InputSource in = new InputSource(new StringReader(xml));


            try {
                XMLReader  reader= SAXParserFactory.newInstance().newSAXParser().getXMLReader();
                SaxProcess p=new SaxProcess();
                reader.setContentHandler(p);
                reader.parse(in);
                logger.info("RESULT \n"+p.getResult());
            } catch (ParserConfigurationException | SAXException | IOException e) {
                e.printStackTrace();
            }

    }

}

Answer 2

似乎你需要一个xml形式的输出，即。您需要xml格式的parent个节点。 SAXParser或XPath引擎使用节点和节点名称。你必须编写特殊的代码来将所需的输出作为xml返回，这可能非常麻烦且难以维护。

轻松获取所需输出xml的一种方法是使用XSLT。

考虑使用XSLT：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:template match="/">
    <xsl:copy-of select="//payload/parent"/>
</xsl:template>
</xsl:stylesheet>

将此文件放在名为parentxslt.xml的文件中，并将输入的xml放在parent.xml中，然后您可以使用以下java代码：

try
{
    File stylesheet = new File( "parentxslt.xml" );
    Transformer transformer = TransformerFactory.newInstance().newTransformer( new StreamSource(stylesheet) );
    StreamSource xmlSource = new StreamSource( new File( "parent.xml" ) );
    StringWriter sw = new StringWriter();
    transformer.transform( xmlSource, new StreamResult( sw ) );

    System.out.println( sw.toString().replaceAll("\\\r\\n\\s*", "") );

}
catch ( Exception ex )
{
   ex.printStackTrace();
}

使用SAX解析器，需要将所有xml元素（在特定元素下）作为字符串

2 个答案: