Question

我创建了LUIS应用程序，包含1个intent（Order Pizza）和9个实体（Order，Kind，Signature，Size，Toppings，address，Time，Duration，Range）。

我需要在Azure Bot Framework中创建一个bot。我无法理解并使用所有实体的瀑布。请让我知道如何去做它

代码：

 dialog.matches('OrderPizza', [
 function (session, args, next) {

   var order = builder.EntityRecognizer.findEntity(args.entities, 'order');
   var kind = builder.EntityRecognizer.findEntity(args.entities, 'Kind');
   session.dialogData.intentScore = args.score;

   if (!order) {
       builder.Prompts.text(session, 'welcome please order pizza');
   } else {
       session.dialogData.order = order;
       next();
   }
 },
 function (session, results) {
   var order = session.dialogData.order;
   if (results.response) {
       session.send('what kind?');
   }else{
       session.send(`we don't have that kind of pizza`);
   }
 }

    ]);

如何进一步推动其他实体？

Answer 1

我不确定你只能写2个函数是什么意思;但如果你想在对话框中调用LUIS，可以按照example进行操作。您将在session.message.text的瀑布步骤中调用LuisRecognizer。示例中的代码段如下：

builder.LuisRecognizer.recognize(session.message.text, '<model url>', function (err, intents, entities) {
   if (entities) {
     var entity = builder.EntityRecognizer.findEntity(entities, 'TYPE');
     // do something with entity...
   }
});

这样您就可以在瀑布内调用LUIS来识别用户的消息。

关于您的代码，存在许多问题：

// Original Code
dialog.matches('OrderPizza', [
  function (session, args, next) {
   var order = builder.EntityRecognizer.findEntity(args.entities, 'order');
   var kind = builder.EntityRecognizer.findEntity(args.entities, 'Kind');
   session.dialogData.intentScore = args.score;

   if (!order) { // What about kind?
       builder.Prompts.text(session, 'welcome please order pizza');
   } else {
       session.dialogData.order = order; // What about kind?
       next();
   }
 },
 function (session, results) {
   var order = session.dialogData.order;
   if (results.response) {
       session.send('what kind?');
   }else{
       session.send(`we don't have that kind of pizza`);
   }
 }
]);

在第一个瀑布步骤中，您没有将"Kind"实体保存到dialogData。

function (session, args, next) {
  var order = builder.EntityRecognizer.findEntity(args.entities, 'order');
  var kind = builder.EntityRecognizer.findEntity(args.entities, 'Kind');
  session.dialogData.intentScore = args.score;

  if (kind) {
    session.dialogData.kind = kind;
  }

  if (!order) {
    builder.Prompts.text(session, 'welcome please order pizza');
  } else {
     session.dialogData.order = order;
     next();
  }
}

在你的第二个瀑布步骤中，你没有打电话给next，也没有向用户发送Prompt，这导致你在两个功能之后被卡住了。

function (session, results, next) {
  var order = session.dialogData.order ? session.dialogData.order : results.response;
  var kind = session.dialogData.kind;

  if (results.response && !kind) {
    builder.Prompts.text(session, 'what kind?');
  } else {
    session.send('we don\'t have that kind of pizza');
    next();
  }
}

如何使用LUIS在Nodejs中使用Waterfall进程

1 个答案: