Question

我需要通过字段dg_id组合数组的值并获得mark和cnt的结果。 dg_id字段值应该是唯一的。请参阅下面的代码

1.Array

Array ( 
    [0] => Array 
                ( 
                [dg_id] => ht01aa 
                [mark] => A 
                [cnt] => 24653 
                ) 
    [1] => Array 
                ( 
                [dg_id] => ht01aa 
                [mark] => O 
                [cnt] => 149 
                ) 
    [2] => Array 
                ( 
                [dg_id] => ht01aa 
                [mark] => U 
                [cnt] => 198 
                ) 
    [3] => Array 
                ( 
                [dg_id] => ht01ab 
                [mark] => A 
                [cnt] => 19259 
                ) 
    [4] => Array 
                ( 
                [dg_id] => ht01ab 
                [mark] => O 
                [cnt] => 121 
                ) 
    [5] => Array 
                ( 
                [dg_id] => ht01ab 
                [mark] => U 
                [cnt] => 153 ) 
                ) 
    )

如何以这种方式获得输出

    +--------+--------+--------+-------+
    | dg_id  |   A    |    O   |   U   |
    +--------+--------+--------+-------+
    | ht01aa |  24653 |    149 |   198 |
    | ht01ab |  19259 |    121 |   153 |

3.我已尝试过代码

        $temp = '';
        echo '<table cellpadding="10px">';
        foreach ($status_array as $key1 => $val1) {
            echo '<tr>';
            foreach ($val1 as $key2 => $val2) {
                if ($key2 == $status_array['dg_id'] && $temp!= $val2) {
                    $temp = $val2;
                    echo "<td><b>" . $val2 . "</b></td>";
                    echo '</tr>';
                }
                else if ($key2 == 'cnt']){
                    echo "<td>" . $val2 . "</td>";
                }
            }
            echo '</tr>';
        }
        echo '</table>';

4.我当前的输出

        dg_Id   A       O     U     
        ht01aa  24653 
        149 
        198 
        ht01ab  19259 
        121 
        153

查询

 $status="select concat(dg,fg,block) as dg_id, mark, count(*) as cnt from ".$table." group by 1,2 limit 15";
 $status_fetch=mysql_query($status,$link1);
 $status_array = array(); 
    while ($row_status = mysql_fetch_array($status_fetch, MYSQL_ASSOC))
        {
         $status_array[] = $row_status;
        }

但没有得到适当的解决方案。任何人帮我解决这个问题..

Answer 1

从查询中获取数组值后，从for each循环开始

 $result_array= Array();
            foreach( $status_array as $fa )
            {
                $result_array[$fa["dg_id"]][($fa["mark"])] += $fa["cnt"];
            }

制作以下内容

Array (  
       [ht01aa] => Array ( 
                          [A] => 24203 
                          [O] => 323 
                          [U] => 474 
                      ) 
       [ht01ab] => Array ( 
                         [A] => 18639 
                         [O] => 392 
                         [U] => 502 
                      ) 
      )

然后通过为每个循环使用另一个循环将数组值分配给表

  foreach ($result_array as $dg_id => $result) 
      {
                $keyA = "A";
                $keyO = "O";
                $keyU = "U";

                echo "<tr>
                          <td>{$dg_id}</td>            
                          <td>{$result[$keyA]}</td>
                          <td>{$result[$keyO]}</td>
                          <td>{$result[$keyU]}</td>
                      </tr>

      }

这适合我：）

如何使用一个匹配值显示数组值并将其显示为表

1 个答案: