Question

我无法找到在Julia中执行以下操作的方法：

输入：x= [["1","2","3"],["4","5","6"],["7","8","9"]]

所需的输出：["1 4 7", "2 5 8","3 6 9"]

基本上，我想生成n个字符串，其中n是x数组的长度，每个字符串都采用如上所示的字符。

有没有办法做到这一点？

修改

经过一番思考后，我得到了以下解决方案，但我不认为这是理想的解决方案。如果我得到一些答案，我仍然很高兴

x= [["1","2","3"],["4","5","6"],["7","8","9"]]
y= hcat(x...)
foo(y) = mapreduce(x->string(x," "),string,y)
mapslices(foo,y,2)

Answer 1

以这种方式：

julia> x= [["1","2","3"],["4","5","6"],["7","8","9"]]
3-element Array{Array{String,1},1}:
 String["1","2","3"]
 String["4","5","6"]
 String["7","8","9"]

julia> [join(k, " ") for k in zip(x...)]
3-element Array{String,1}:
 "1 4 7"
 "2 5 8"
 "3 6 9"

julia>

Answer 2

我喜欢瑞克的单行，但我不得不说，我不确定你为什么要寻找一种“聪明”的方式。 For循环在julia中非常有效，这是一个简单的嵌套for循环：

julia> StrList = Array{String, 1}()  # initialise an empty String Array
0-element Array{String,1}

julia> rows = length(x);

julia> for col in 1:length(x[1])
         s = "";                   # empty placeholder string
         for row in 1:(rows-1); 
           s *= x[row][col] * " "; # add N-1 elements with space
         end
         s *= x[rows][col];        # add Nth element without space
         push!(StrList, s); 
       end

julia> StrList
3-element Array{String,1}:
 "1 4 7"
 "2 5 8"
 "3 6 9"

如何在Julia中合并数组数组的元素

2 个答案: