Question

我需要一个显示当天记录的解决方案并显示每列的SUM，到目前为止我有一个查询来显示联合记录，如：

SELECT 
    datetime, 
    remarks, 
    void, 
    invoice, 
    reload, 
    redeem 
FROM
    (
      SELECT datetime, remarks, '' void, '' invoice, points_intake reload, '' redeem, 1 ord
      FROM bpp_intake_logs
      WHERE outlet = 'KUL' AND DATE(datetime) = '2017-06-13'
      UNION ALL

      SELECT datetime, remarks, void, invoice, '', points_consume, 2
      FROM bpp_consume_logs
      WHERE outlet = 'KUL' AND DATE(datetime) = '2017-06-13' 
    ) q
ORDER BY datetime DESC, ord

，结果表显示如下：

datetime            | remarks                        | void | invoice  | reload | redeem |
2017-06-13 15:53:31 | Point restored - void XY203460 |      |          | 10     |        |
2017-06-13 15:37:27 | reload / top-up credit         |      |          | 10     |        |
2017-06-13 15:35:56 | redeem from VIP card           |  1   | XY203460 |        | 10     |
2017-06-13 15:16:03 | redeem from VIP card           |      | XY203456 |        | 5      |

现在，我想添加一个单元格，对其所属列底部的每个reload和redeem求和，如：

datetime            | remarks                        | void | invoice  | reload | redeem |
2017-06-13 15:53:31 | Point restored - void XY203460 |      |          | 10     |        |
2017-06-13 15:37:27 | reload / top-up credit         |      |          | 10     |        |
2017-06-13 15:35:56 | redeem from VIP card           |  1   | XY203460 |        | 10     |
2017-06-13 15:16:03 | redeem from VIP card           |      | XY203456 |        | 5      |
                                                                       | 20     | 15     |

如图所示，SUM 20 和 15 分配在底部单元格中。

这可能以这种方式获得结果吗？

Answer 1

也许这就是你要找的????

SELECT 
datetime, 
remarks, 
void, 
invoice, 
SUM(reload), 
SUM(redeem) 
FROM
(
  SELECT datetime, remarks, '' void, '' invoice, points_intake reload, '' redeem, 1 ord
  FROM bpp_intake_logs
  WHERE outlet = 'KUL' AND DATE(datetime) = '2017-06-13'
  UNION ALL

  SELECT datetime, remarks, void, invoice, '', points_consume, 2
  FROM bpp_consume_logs
  WHERE outlet = 'KUL' AND DATE(datetime) = '2017-06-13' 
) q
GROUP BY datetime desc, remarks asc, void asc, invoice asc with rollup

ORDER BY datetime DESC, ord

MySQL union和sum两个表

1 个答案: