Question

我是一个非常新的编码用户，我写了一个小的python脚本，但有一些格式问题我无法解决，你能不能给出一些建议？

   while(True):
        keyword = "edit clients are "
        p = buf.find(keyword)
        if(p == -1):
            break

        p = buf.find(keyword)
        usage_count = int(buf[:p].split())
        buf = buf[p+len(keyword):]
        print "================== %s usage_count" % usage_count


        ret.append(LicenseSitRep(usage_count))

    return ret

输出结果显示：

TypeError: int() argument must be a string or a number, not 'list'

我的搜索值低于，我的预期输出应为11.

Jun 14 11:01:58 license server: Current accepted edit clients are 11.

Answer 1

错误来自此行

usage_count = int(buf[:p].split())

原因是split函数返回list而不是str，您可以更改代码。

usage_count = int(buf[:p].split()[0])

修改

要获取11，您可以从调试过程中找到。

[in] buf = r"Jun 14 11:01:58 license server: Current accepted edit clients are 11." [in] p = 49 [in] buf[p:] [out] 'edit clients are 11.' [in] buf[:p] [out] 'Jun 14 11:01:58 license server: Current accepted ' [in] buf[p:].split(" ") ['edit', 'clients', 'are', '11.'] [in] buf[p:].split(" ")[-1] [out] '11.' [in] buf[p:].split(" ")[-1].split(".") [out] ['11', ''] [in] buf[p:].split(" ")[-1].split(".")[0] [out] '11'

你可以试试这段代码。

usage_count = int(buf[p:].split(" ")[-1].split(".")[0])

Answer 2

为什么不通过re来利用正则表达式而只是这样做？

import re 
buf = "Jun 14 11:01:58 license server: Current accepted edit clients are 11."
# ...
p = buf.find(keyword)
buf = buf[p+len(keyword):]
buf = int(re.sub(r'[^\w]', ' ', buf))
usage_count = buf

Answer 3

使用正则表达式更可行我猜

import re
buf = "Jun 14 11:01:58 license server: Current accepted edit clients are 11."
if bool(re.match(r'.*edit\sclients\sare\s\d+.$', buf)):
    usage_count = re.findall(r'edit\sclients\sare\s(\d+?)\.', buf)
    print "================== %s usage_count" % usage_count[0]

启动Python程序得到一些字符串格式问题

3 个答案: