Question

如何检查刽子手游戏的重复输入（字母）？

示例：

字是苹果

输入是猜一封信：a

输出很好！

然后猜猜下一个字

输入是猜一封信：a

输出应该是你猜的那封信。

我的代码：

def checkValidGuess():
word = getHiddenWord()
lives = 10
num = ["1","2","3","4","5","6","7","8","9",]
#guessed = ''
while lives != 0 and word:
    print("\nYou have", lives,"guesses left")
    letter = input("Guess a letter or enter '0' to guess the word: ")
    if letter.lower() in word:
        print("Well done!", letter, "is in my word!")
        lives -= 1
    elif len(letter)>1:
        print("You can only guess one letter at a time!")
        print("Try again!")
    elif letter in num:
        print("You can only input letter a - z!")
        print("Try again!")
    #elif letter in guessed:
        #print("repeat")
    elif letter == "0":
        wword = input("What is the word?").lower()
        if wword == word:
            print("Well done! You got the word correct!")
            break
        else:
            print("Uh oh! That is not the word!")
            lives -= 1
    #elif letter == "":
        #print("Uh oh! the letter you entered is not in my word.")
        #print("Try again!")
    else:
        print("Uh oh! the letter you entered is not in my word.")
        print("Try again!")
        lives -= 1

感谢。

Answer 1

您可以将输入存储在列表中，我们称之为temp。

然后，当用户输入新信件时，您可以检查列表中是否存在输入。

guess = input()
if guess in temp:
    print "You've already guessed {}".format(guess)
else:
    #do whatever you want

Answer 2

这是一个简单的方法。首先初始化一个列表：

guesses = []

然后在你的循环中：

letter = input("Guess a letter or enter '0' to guess the word: ")

if letter in guesses:
    print("Already guessed!")
    continue

guesses.append(letter)

Answer 3

因此，您可能希望在计划中反转支票的顺序，以便首先处理再试一次。在更改之后，添加另一个条件，确定该字母是否与已经猜到的字母匹配。这导致类似：

already_guessed = set()  # I made this a set to only keep unique values

while lives > 0 and word: # I changed this to test > 0
    print(f"\nYou have {lives} guesses left") # I also added an f-string for print formatting
    letter = input("Guess a letter or enter '0' to guess the word: ")
    if len(letter) > 1:
        print("You can only guess one letter at a time!")
        print("Try again!")
        continue # If you reach this point, start the loop again!
    elif letter in already_guessed:
        print("You already guessed that!")
        print("Try again")
        continue
    elif letter in num:
        print("You can only input letter a - z!")
        print("Try again!")
        continue
    elif letter.lower() in word:
        print("Well done!", letter, "is in my word!")
        lives -= 1
    else:  
        already_guessed.update(letter)
        # It wasn't a bad character, etc. and it wasn't in the word\
        # so add the good character not in the word to your already guessed 
        # and go again!

您需要添加其他条件分支，但这应该可以帮助您。祝你好运。

检查输入中的重复（Python）

3 个答案: