Question

嘿我的登录脚本有问题。当我尝试在if语句中访问变量时，它们就像无法被访问一样，就像它们是私有的一样。我已经尝试使用PHP $ GLOBALS 使其全局化，但我没有成功。这是一些示例代码。

<?php
    $error = array();
    $username = $_POST['username'];
    $password = $_POST['password'];
    if(empty($username)){
        $error[] = 'Username can not be empty'; //This will show error
    }elseif(empty($password)){
        $error[] = 'Password can not be empty'; //This will show error
    }elseif(empty($error)){
        $stmt = $pdo->prepare("SOME QUERY");
        $stmt -> execute(array(':username' => $username, ':password' => $password));
        $count = $stmt -> fetchColumn(0);
        if($count == 1){
        $stmt = $pdo->prepare("SOME QUERY");
        $stmt -> execute(array(':username' => $username, ':password' => $password));
        $results = $stmt->fetch(PDO::FETCH_ASSOC);
                if($results['status'] == 1){
                    $error[] = 'you are banned'; //This will not show error
                }
        }
    }else{
        foreach($error as $alert){
        $errors = '<p><b>example</b>' . $alert . '</p>';
        }
    }
?>
<html>
    <head>
        <title>Example</title>
    </head>
    <body>
        <?php echo (!empty($errors) ? $errors : ''); ?>
    </body>
</html>

Answer 1

有些地方有$error，有些地方有$errors。如果所有变量引用的拼写相同，那么它应该可以正常工作。

Answer 2

试试此代码，经过测试

<?PHP


if(isset($_POST["submit"])){

if(empty($_POST['username'])){

$error[] = 'Username Cannot Be Empty';  

}elseif(empty($_POST['password'])){

$error[] = 'Password Cannot Be Empty';  

}else{


        $username = $_POST['username'];
        $password = $_POST['password']; 

        $stmt = $db->prepare('SELECT * FROM user WHERE username = :username');
        $stmt->bindParam(':username', $_POST['username'], PDO::PARAM_STR, 16);
        $stmt->execute(array(':username' => $_POST['username']));
        $row = $stmt->fetch(PDO::FETCH_ASSOC);

        if(!empty($row['username'])){

        if($password==$row['password']){


        if($row['status']==1){

              $error[] = 'you are banned'; 

        }else{

        header("Location: index.php"); //valid login will redirect to another page

        }

        }elseif($password!=$row['password']){

        $error[] = 'Invalid Username / Password';       

        }

        }else{

        $error[] = 'Invalid Username';      

        }


}
}

?>

    <?PHP
                    //check for any errors
                    if(isset($error)){
                        foreach($error as $error){
                            echo '<p >'.$error.'</p>';
                        }
                    }

                    ?>

PHP中无法访问的变量

2 个答案: