我有一个像这样的列表
[[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
必需的输出:
[{1:"one",2:"two"},{1:"one"},{3:"three",4:"four"},{3:"three"}]
有人可以告诉我如何继续吗?
答案 0 :(得分:1)
迭代列表的列表,将其添加到另一个列表中。
list_1 = [[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
list_2 = []
for list in list_1:
for dictionary in list:
list_2.append(dictionary)
print(list_2) # [{1: 'one', 2: 'two'}, {1: 'one'}, {3: 'three', 4: 'four'}, {3: 'three'}]
答案 1 :(得分:0)
你可以试试这个:
from itertools import chain
l = [[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
new_l = list(chain(*l))
最终输出:
[{1: 'one', 2: 'two'}, {1: 'one'}, {3: 'three', 4: 'four'}, {3: 'three'}]