IFELSE [比较两个单独列表的长度] [ACT]

Question

根据我的问题yesterday，我尝试使用filter和length来实施代码。我想我已经实现了filter但现在我需要代理将它们的列表长度与其他代理（活动）列表进行比较。这是我的代码：

ask agentes [
  set culture-tags n-values 17 [random 2]
  set shared-culture (filter [ i -> i = 0 ] culture-tags)  ;count 0s and 
                                                            create shared-culture
]
end

to move-agentes
  ask agentes [
    let nearest-activity min-one-of (activities) [ distance myself ] 
    ifelse any? activities in-radius sight-radius with
      [ length t-shared-culture = length shared-culture ] ;as many 0s in t-shared-culture (specified later in the setup for activities) as in shared-culture
    [  face nearest-activity ]
    [ rt random 40 
      lt random 40
      fd 0.3
    ]
]

Netlogo打印下一个错误："ACTIVITIES breed does not own variable SHARED-CULTURE error while activity 176 running SHARED-CULTURE"。 我想错误必须在这里：[ length t-shared-culture = length shared-culture ]但我不知道如何让两个列表进行交互。