Question

有没有办法在下面的公式中使用变量作为动态数字，所以当对手在id列中更改时，我可以将4game_so_ct数重置为零。我也尝试按id排序，只是明确地将它们全部按顺序排列，并且不重置数字。第4game列是前面要查看的行数，以获取id相同的前一行数。

 sum(strikeouts) over (order by game_dt rows between 3 preceding and current row) as 4game_so_ct

我尝试了什么

 sum(strikeouts) over (order by game_dt rows between 4game preceding and current row) as 4game_so_ct

但它明显错误。

我有一张如下表格

GAME_ID         GAME_DT HOME_TEAM_ID    AWAY_TEAM_ID    id  strikeouts  4game   test    4game_so_ct
WS1192204120    19220412    WS1              NYA      NYAWS1    4          0     0       4
BOS192204180    19220418    BOS              NYA      NYABOS    2          0    NYAWS1   2
NYA192204210    19220421    NYA              WS1      WS1NYA    1          0    NYABOS   1
NYA192204220    19220422    NYA              WS1      WS1NYA    2          1    WS1NYA   2
NYA192204230    19220423    NYA              WS1      WS1NYA    0          2    WS1NYA   0
NYA192204250    19220425    NYA              PHA      PHANYA    1          0    WS1NYA   1
NYA192204260    19220426    NYA              PHA      PHANYA    4          1    PHANYA   4
NYA192204280    19220428    NYA              BOS      BOSNYA    0          0    PHANYA   0
NYA192204290    19220429    NYA              BOS      BOSNYA    6          1    BOSNYA   6
NYA192204300    19220430    NYA              BOS      BOSNYA    4          2    BOSNYA   4
NYA192205010    19220501    NYA              BOS      BOSNYA    2          3    BOSNYA   2
NYA192205020    19220502    NYA              BOS      BOSNYA    1          4    BOSNYA   1

我希望在4game_so_ct列

中看到什么

GAME_ID         GAME_DT HOME_TEAM_ID    AWAY_TEAM_ID    id  strikeouts  4game   test    4game_so_ct
WS1192204120    19220412    WS1              NYA      NYAWS1    4          0     0       4
BOS192204180    19220418    BOS              NYA      NYABOS    2          0    NYAWS1   2
NYA192204210    19220421    NYA              WS1      WS1NYA    1          0    NYABOS   1
NYA192204220    19220422    NYA              WS1      WS1NYA    2          1    WS1NYA   3
NYA192204230    19220423    NYA              WS1      WS1NYA    0          2    WS1NYA   3
NYA192204250    19220425    NYA              PHA      PHANYA    1          0    WS1NYA   1
NYA192204260    19220426    NYA              PHA      PHANYA    4          1    PHANYA   5
NYA192204280    19220428    NYA              BOS      BOSNYA    0          0    PHANYA   0
NYA192204290    19220429    NYA              BOS      BOSNYA    6          1    BOSNYA   6
NYA192204300    19220430    NYA              BOS      BOSNYA    4          2    BOSNYA   10
NYA192205010    19220501    NYA              BOS      BOSNYA    2          3    BOSNYA   12
NYA192205020    19220502    NYA              BOS      BOSNYA    1          4    BOSNYA   13

Answer 1

你过度复杂了。在partition by中使用SUM，这是预期的结果。

sum(strikeouts) over (partition by id order by game_dt)

Answer 2

语法图可能有点难以理解。但是documentation很清楚窗框规范需要是一个常数：

<window frame preceding> ::=   
{  
    UNBOUNDED PRECEDING  
  | <unsigned_value_specification> PRECEDING  
  | CURRENT ROW  
}  
 . . .
<unsigned value specification> ::=   
{  <unsigned integer literal> }

因此，使用Windows框架规范无法实现所需。

按行与变量排序

2 个答案: