Question

抱歉，我今天遇到错误

Parser Error 
    Description: An error occurred during the parsing of a resource required to service this request. Please review the following specific parse error details and modify your source file appropriately. 

    Parser Error Message: System.Web.UI.WebControls.DataControlFieldCollection must have items of type 'System.Web.UI.WebControls.DataControlField'. 'ItemTemplate' is of type 'System.Web.UI.HtmlControls.HtmlGenericControl'.

    Source Error: 


    Line 66:                            
    Line 67: <asp:TemplateField HeaderText="AS of" & label2.text>
    Line 68: <ItemTemplate>
    Line 69:  <%#Getsales(Decimal.Parse(Eval("AsOFSales").ToString())).ToString("C0")%>
    Line 70: </ItemTemplate>

Answer 1

您无法在ASP.NET标记中使用VB.NET代码。如果要更改HeaderText，请在代码隐藏中执行此操作。

Answer 2

正如TA先生所说，你需要从你的代码中做出这些改变。类似下面的代码 - 只需更换？在单元格（？）中使用网格中列号的（基于零的索引）（或w

Protected Sub DataGrid1_ItemDataBound(ByVal sender As Object, ByVal e As DataGridItemEventArgs) handles DataGrid1.ItemDataBound
    If (e.Item.ItemType = ListItemType.Header) Begin
       e.Item.Cells(?).Text = "AS of" & label2.text
    End If
End Sub

Answer 3

你不能这样做：

Line 67: <asp:TemplateField HeaderText="AS of" & label2.text>

最好将其留空并在RowDataBound事件期间将其设置在后面的代码中。

Protected Sub myGridView_RowDataBound(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewRowEventArgs) Handles myGridView.RowDataBound
    If e.Row.RowType = DataControlRowType.Header Then
        Dim e.Row.Cells(2).Text = "As of " & Label2.Text
    End If
End Sub

这假设您没有在GridView上启用排序。如果确实启用了排序，则首先必须找到LinkButton控件并更改其文本值。我还在Cells标识符中使用了任意值2。您需要使用所需单元格的数字列号。

使用标签文本作为我的gridview标题的一部分的问题

3 个答案: