Question

我是python的新手，我想在python3中清理并重新格式化列表来自：

[['', '\xa0', '', ''], ['First Standard', 'First Flex', 'Business 
Standard','Business Flex', 'Economy standard', 'Economy Flex', 'Economy 
Saver', 'Economy Superdeal'], ['Class', 'P/F', 'A', 'C/D', ' Z/J', 'W/Y/B/M 
', 'H/K/L', 'Q/G/V/E', 'S/T/U/N'], ['Change Fee\nIn']]

到

['First Standard', 'First Flex', 'Business Standard', 'Business Flex', 
'Economy standard', 'Economy Flex', 'Economy Saver', 'Economy Superdeal'], 
['Class','P/F', 'A', 'C/D', ' Z/J', 'W/Y/B/M ', 'H/K/L', 'Q/G/V/E', 
'S/T/U/N']

Answer 1

这是一种不是特别干净但不言自明的方式：

old = [['', '\xa0', '', ''], ['First Standard', 'First Flex', 'Business Standard', 'Business Flex', 'Economy standard', 'Economy Flex', 'Economy Saver', 'Economy Superdeal'], ['Class', 'P/F', 'A', 'C/D', ' Z/J', 'W/Y/B/M ', 'H/K/L', 'Q/G/V/E', 'S/T/U/N'], ['Change Fee\nIn']]

new = []
for old_element in old:
    new_element = []

    for string in old_element:
        stripped = string.strip()

        if stripped:
            new_element.append(stripped)

    if new_element:
        new.append(new_element)

print new

修改

仍然在等待对问题的更好解释，但是如果你只想删除第一个和最后一个元素，你可以像@salparadise那样说，或者像下面这样的东西，这有点笼统：< / p>
old = [['', '\xa0', '', ''], ['First Standard', 'First Flex', 'Business Standard', 'Business Flex', 'Economy standard', 'Economy Flex', 'Economy Saver', 'Economy Superdeal'], ['Class', 'P/F', 'A', 'C/D', ' Z/J', 'W/Y/B/M ', 'H/K/L', 'Q/G/V/E', 'S/T/U/N'], ['Change Fee\nIn']] # 1 means the second element of the list, because 0 is the first. # -1 means "one element back from the end of the list". new = old[1:-1]

Answer 2

假设您需要两个单独的列表，并且您的第一个列表是：

       <plugin>
            <groupId>net.masterthought</groupId>
            <artifactId>maven-cucumber-reporting</artifactId>
            <version>${masterThougth.version}</version>
            <executions>
                <execution>
                    <id>execution</id>
                    <phase>verify</phase>
                    <goals>
                        <goal>generate</goal>
                    </goals>
                    <configuration>
                        <checkBuildResult>false</checkBuildResult>
                        <projectName>${project.artifactId}</projectName>
                        <buildNumber>${project.build}</buildNumber>
                        <parallelTesting>true</parallelTesting>
                        <outputDirectory>target/cucumber-report/</outputDirectory>
                        <cucumberOutput>target/cucumber-report/</cucumberOutput>
                    </configuration>
                </execution>
            </executions>
        </plugin>

您可以使用python的解包魔法来获取内部列表并将其转储到两个不同的列表中：

[['', '\xa0', '', ''],
 ['First Standard',
  'First Flex',
  'Business Standard',
  'Business Flex',
  'Economy standard',
  'Economy Flex',
  'Economy Saver',
  'Economy Superdeal'],
 ['Class',
  'P/F',
  'A',
  'C/D',
  ' Z/J',
  'W/Y/B/M ',
  'H/K/L',
  'Q/G/V/E',
  'S/T/U/N'],
 ['Change Fee\nIn']]

文本文件清理，格式化和对齐

2 个答案: