我正在尝试开发一种在excel(VBA)中提问的方法。提问将以先前的答案为条件,或者继续进行问题集应变,或者如果没有出现在下一个问题集应变中。最后,如果每个应变,如果达到,id就像保存答案并将它们全部汇总到最后。
我会尝试放一些我已经开始的代码,但我不知道怎么做,甚至不确定它是否可能。
我添加了一幅关于如何设想逻辑的图片。
如果有人能提供帮助那就太棒了!
答案 0 :(得分:0)
为了给你一些开始,试试这个:
Sub Questions()
Dim Answers() As String, strTemp As String
Dim SetCount As Integer, QCount As Integer
SetCount = 3 'Question Sets
QCount = 4 'Max Number of Question
ReDim Answers(SetCount, QCount) 'Stores Answers
For i = 1 To SetCount 'Loop trough Sets
For j = 1 To QCount 'Loop trough Question
Answers(i, j) = Message(Q(i & j), i) 'Message Returns Answers of Set i and Question j
If Answers(i, j) = "" Or Answers(i, j) = "No" Then 'Exit if no more Question or "No"
Exit For
End If
Next j
Next i
'Output
For i = 1 To SetCount
strTemp = strTemp & "Set" & i & ":" & vbNewLine
For j = 1 To QCount
strTemp = strTemp & vbTab & "Question " & j & ":" & Answers(i, j) & vbNewLine
Next j
strTemp = strTemp & vbNewLine
Next i
MsgBox (strTemp) 'Print Answers
End Sub
Function Message(ByVal Question As String, ByVal Title As String) As String
If Question <> "Nothing" Then 'Valid Answers
If MsgBox(Question, vbYesNo, Title) = vbYes Then
Message = "Yes"
Else
Message = "No"
End If
Else
Message = "" 'No more Questions
End If
End Function
Function Q(ByVal Question As Integer) As String
'Stores Questions
Select Case Question
Case 11: Q = "Set 1 Question 1"
Case 12: Q = "Set 1 Question 2"
Case 13: Q = "Set 1 Question 3"
Case 21: Q = "Set 2 Question 1"
Case 22: Q = "Set 2 Question 2"
Case 23: Q = "Set 2 Question 3"
Case 24: Q = "Set 2 Question 4"
Case 31: Q = "Set 3 Question 1"
Case 32: Q = "Set 3 Question 2"
Case Else: Q = "Nothing"
End Select
End Function
问题存储在函数Q
中。它将在“是”上继续使用相同的设置,并跳转到“否”上的下一组。添加新问题/集时,必须调整SetCount
和QCount
。