Question

我有一个基本上看起来像这样的JSON：

{
    "body": 
    {
        "mode": "raw",
        "raw": "{
            \"Token\" : \"123123\", \"queryName\" : \"testMethod\" ,\"dataTestToSEND\" :{\"IDs\":[\"B00448MZUW\",\"B071F7LBN6\",\"B01BBZJZHQ\"],\"Marketplace\":\"southAmerica\",\"Region\":\"West\",\"PricingMethod\":0}} "a
        },
        "description": "some description here"
    }
}

当我将它转换为C＃对象类时，我得到了这个：

public class Body
{
    public string mode { get; set; }
    public string raw { get; set; }
}

public class RootObject
{
    public Body body { get; set; }
    public string description { get; set; }
}

我在这里使用了json2csharp工具..

现在让我感到困惑的是你可以看到的“原始”属性..这个工具把它转换成了一个字符串，但这对我来说真的不像是一个字符串？

相反，原始的，我看到它的方式，应该是一个包含这样的东西的类：

public class Raw
{
    public string Token { get; set; }
    public string queryName { get; set; }
    public List<string//?not sure which type does this needs to be set to?> 
    dataTestToSEND { get; set }
    public string marketplace { get; set; }
    public string Region { get; set }
}

有人可以帮我解决这个问题吗？如何为此JSON构建一组适当的类和对象？这对我来说非常困惑......

Answer 1

json2csharp将您的原始属性转换为字符串，因为它无法使用转义字符正确解析JSON文档。删除转义字符，以便让json2csharp创建正确的尖锐类。

{"body":{"mode":"raw","raw":{"Token":"123123","queryName":"testMethod","dataTestToSEND":{"IDs":["B00448MZUW","B071F7LBN6","B01BBZJZHQ"],"Marketplace":"southAmerica","Region":"West","PricingMethod":0}}},"description":"somedescriptionhere"}

Answer 2

您可以使用JSON.NET将您的json转换为特定类

官方网站：http://www.newtonsoft.com/json

你可以从json中删除反斜杠，让JObject解释它。

public class Raw
{
    public Raw(string json)
    {
        JObject jObject = JObject.Parse(json);
        JToken jRaw = jObject["raw"];
        Token = (string) jRaw["token"];
        queryName = (string) jRaw["queryName"];
        dataTestToSEND = (List<string>) jRaw["dataTestToSEND"];
        marketplace = (string) jRaw["Marketplace"]
        Region= jRaw["players"].ToArray();
    }

    public string Token {get;set;}
    public string queryName {get;set;}
    public List<string> dataTestToSEND {get;set}
    public string marketplace {get;set;}
    public string Region{get;set}



}

// Call User with your json
string json = @"{""body"":{""mode"":""raw"",""raw"":{""Token"":""123123"",""queryName"":""testMethod"",""dataTestToSEND"":{""IDs"":[""B00448MZUW"",""B071F7LBN6"",""B01BBZJZHQ""],""Marketplace"":""southAmerica"",""Region"":""West"",""PricingMethod"":""0""}}},""description"":""somedescriptionhere""}";
Raw raw = new Raw(json);

Answer 3

构建自定义转换器以将字符串属性转换为类型

public class RawConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return true;
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType != JsonToken.String)
        {
            throw new InvalidOperationException();
        }
        var value = (string)reader.Value;
        var obj = JsonConvert.DeserializeObject(value, objectType);
        return obj;
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var str = JsonConvert.SerializeObject(value);
        writer.WriteValue(str);
    }
}

并在您需要转换器的属性上放置一个属性

public class Body
{
    public string mode { get; set; }
    // This property is a raw string in the json document
    [JsonConverter(typeof(RawConverter))]
    public Data raw { get; set; }
}

public class RootObject
{
    public Body body { get; set; }
    public string description { get; set; }
}

public class Data
{
    public string Token { get; set; }
    public string queryName { get; set; }
    public DataTestToSEND dataTestToSEND { get; set; }
}

public class DataTestToSEND
{
    public string[] IDs { get; set; }
    public string Marketplace { get; set; }
    public string Region { get; set; }
    public int PricingMethod { get; set; }
}

现在你可以反序列化给定的json

{
  "body": {
    "mode": "raw",
    "raw": "{\"Token\":\"123123\",\"queryName\":\"testMethod\",\"dataTestToSEND\":{\"IDs\":[\"B00448MZUW\",\"B071F7LBN6\",\"B01BBZJZHQ\"],\"Marketplace\":\"southAmerica\",\"Region\":\"West\",\"PricingMethod\":0}}"
  },
  "description": "some description here"
}

与

var result = JsonConvert.DeserializeObject<RootObject>( jsonString );

使用反序列化和序列化

在.net fiddle上的实例

将JSON转换为C＃对象类

3 个答案: