美好的一天，
我有一个显示如下的文件：
Bin 1 = 5778 669 753 731 743 752 727 736 667
Bin 5 = 2 2 0 0 0 0 0 0 0 Bin 7 = 63 36 5 1 1 5 1 5 9
Bin 9 = 0 0 0 0 0 0 0 0 0 Bin 24 = 2 0 0 0 0 0 0 0 2
Bin 31 = 0 0 0 0 0 0 0 0 0 Bin 47 = 28 2 4 6 1 2 5 3 5
Bin 70 = 1 0 0 0 0 0 1 0 0 Bin 95 = 1 0 1 0 0 0 0 0 0
Bin 120 = 1 0 1 0 0 0 0 0 0 Bin 121 = 162 49 13 11 10 3 10 12 54
Bin 131 = 7 1 1 2 0 0 1 0 2 Bin 133 = 3 0 0 0 0 0 0 0 3
Bin 141 = 6 0 0 0 1 0 1 2 2 Bin 560 = 1 0 0 0 1 0 0 0 0
Bin 620 = 1 0 0 0 1 0 0 0 0 Bin 630 = 2 0 0 1 0 0 0 0 1
Bin 1250 = 1 0 0 0 0 0 1 0 0 Bin 1410 = 1 0 1 0 0 0 0 0 0
Bin 2004 = 1 0 0 0 0 0 0 1 0 Bin 2240 = 1 0 0 0 0 1 0 0 0
Bin 2247 = 1 0 0 1 0 0 0 0 0 Bin 2300 = 1 0 0 0 0 1 0 0 0
Bin 2309 = 1 0 0 0 1 0 0 0 0 Bin 2310 = 3 1 1 0 0 0 0 0 1
Bin 2602 = 1 0 0 0 1 0 0 0 0
我想在右侧剪切第二个“Bin”模式及其值，然后将其粘贴到文件的底部，然后再对其进行排序。感谢你对我这个问题的帮助。我是unix命令的新手，还在学习它。提前谢谢。
我想有这样的输出。
Bin 1 = 5778 669 753 731 743 752 727 736 667
Bin 5 = 2 2 0 0 0 0 0 0 0
Bin 7 = 63 36 5 1 1 5 1 5 9
Bin 9 = 0 0 0 0 0 0 0 0 0
Bin 24 = 2 0 0 0 0 0 0 0 2
Bin 31 = 0 0 0 0 0 0 0 0 0
Bin 47 = 28 2 4 6 1 2 5 3 5
Bin 70 = 1 0 0 0 0 0 1 0 0
Bin 95 = 1 0 1 0 0 0 0 0 0
Bin 120 = 1 0 1 0 0 0 0 0 0
Bin 121 = 162 49 13 11 10 3 10 12 54
Bin 131 = 7 1 1 2 0 0 1 0 2
Bin 133 = 3 0 0 0 0 0 0 0 3
Bin 141 = 6 0 0 0 1 0 1 2 2
Bin 560 = 1 0 0 0 1 0 0 0 0
Bin 620 = 1 0 0 0 1 0 0 0 0
Bin 630 = 2 0 0 1 0 0 0 0 1
Bin 1250 = 1 0 0 0 0 0 1 0 0
Bin 1410 = 1 0 1 0 0 0 0 0 0
Bin 2004 = 1 0 0 0 0 0 0 1 0
Bin 2240 = 1 0 0 0 0 1 0 0 0
Bin 2247 = 1 0 0 1 0 0 0 0 0
Bin 2300 = 1 0 0 0 0 1 0 0 0
Bin 2309 = 1 0 0 0 1 0 0 0 0
Bin 2310 = 3 1 1 0 0 0 0 0 1
Bin 2602 = 1 0 0 0 1 0 0 0 0
方面，麦克
答案 0 :(得分：2)
短 awk 方法：
awk 'NF>12{ $13= ORS $13 }1' file | column -t
NF - 字段总数
NF>12 - 根据您的预期结果，最大字段数为12. 非空白序列被视为字段
$13= ORS $13 - 使用记录分隔符ORS（换行符）分隔第13个字段的记录
输出：
Bin 1 = 5778 669 753 731 743 752 727 736 667
Bin 5 = 2 2 0 0 0 0 0 0 0
Bin 7 = 63 36 5 1 1 5 1 5 9
Bin 9 = 0 0 0 0 0 0 0 0 0
Bin 24 = 2 0 0 0 0 0 0 0 2
Bin 31 = 0 0 0 0 0 0 0 0 0
Bin 47 = 28 2 4 6 1 2 5 3 5
Bin 70 = 1 0 0 0 0 0 1 0 0
Bin 95 = 1 0 1 0 0 0 0 0 0
Bin 120 = 1 0 1 0 0 0 0 0 0
Bin 121 = 162 49 13 11 10 3 10 12 54
Bin 131 = 7 1 1 2 0 0 1 0 2
Bin 133 = 3 0 0 0 0 0 0 0 3
Bin 141 = 6 0 0 0 1 0 1 2 2
Bin 560 = 1 0 0 0 1 0 0 0 0
Bin 620 = 1 0 0 0 1 0 0 0 0
Bin 630 = 2 0 0 1 0 0 0 0 1
Bin 1250 = 1 0 0 0 0 0 1 0 0
Bin 1410 = 1 0 1 0 0 0 0 0 0
Bin 2004 = 1 0 0 0 0 0 0 1 0
Bin 2240 = 1 0 0 0 0 1 0 0 0
Bin 2247 = 1 0 0 1 0 0 0 0 0
Bin 2300 = 1 0 0 0 0 1 0 0 0
Bin 2309 = 1 0 0 0 1 0 0 0 0
Bin 2310 = 3 1 1 0 0 0 0 0 1
Bin 2602 = 1 0 0 0 1 0 0 0 0
答案 1 :(得分：1)
sed 's/ \(Bin.*\)$/\n\1/g' file | sort -k 2 -n > outputfile
这将搜索以空格开头的字符串，后跟＆＃34; Bin＆＃34;以及直到剩余线路的任何角色
可以使用\1在命令的替换部分中引用放入转义的parantheses的部分。在那里你插入一个换行符。
排序部分采用参数
输出：
# sed 's/ \(Bin.*\)$/\n\1/g' your_file | sort -k 2 -n
Bin 1 = 5778 669 753 731 743 752 727 736 667
Bin 5 = 2 2 0 0 0 0 0 0 0
Bin 7 = 63 36 5 1 1 5 1 5 9
Bin 9 = 0 0 0 0 0 0 0 0 0
Bin 24 = 2 0 0 0 0 0 0 0 2
Bin 31 = 0 0 0 0 0 0 0 0 0
Bin 47 = 28 2 4 6 1 2 5 3 5
Bin 70 = 1 0 0 0 0 0 1 0 0
Bin 95 = 1 0 1 0 0 0 0 0 0
Bin 120 = 1 0 1 0 0 0 0 0 0
Bin 121 = 162 49 13 11 10 3 10 12 54
Bin 131 = 7 1 1 2 0 0 1 0 2
Bin 133 = 3 0 0 0 0 0 0 0 3
Bin 141 = 6 0 0 0 1 0 1 2 2
Bin 560 = 1 0 0 0 1 0 0 0 0
Bin 620 = 1 0 0 0 1 0 0 0 0
Bin 630 = 2 0 0 1 0 0 0 0 1
Bin 1250 = 1 0 0 0 0 0 1 0 0
Bin 1410 = 1 0 1 0 0 0 0 0 0
Bin 2004 = 1 0 0 0 0 0 0 1 0
Bin 2240 = 1 0 0 0 0 1 0 0 0
Bin 2247 = 1 0 0 1 0 0 0 0 0
Bin 2300 = 1 0 0 0 0 1 0 0 0
Bin 2309 = 1 0 0 0 1 0 0 0 0
Bin 2310 = 3 1 1 0 0 0 0 0 1
Bin 2602 = 1 0 0 0 1 0 0 0 0
答案 2 :(得分：0)
如果文本是结构化的，那么cut就足够了，例如：
(cut -c1-56 infile; cut -c62- infile) | sort -k2n
输出：
Bin 1 = 5778 669 753 731 743 752 727 736 667
Bin 5 = 2 2 0 0 0 0 0 0 0
Bin 7 = 63 36 5 1 1 5 1 5 9
Bin 9 = 0 0 0 0 0 0 0 0 0
Bin 24 = 2 0 0 0 0 0 0 0 2
Bin 31 = 0 0 0 0 0 0 0 0 0
Bin 47 = 28 2 4 6 1 2 5 3 5
Bin 70 = 1 0 0 0 0 0 1 0 0
Bin 95 = 1 0 1 0 0 0 0 0 0
Bin 120 = 1 0 1 0 0 0 0 0 0
Bin 121 = 162 49 13 11 10 3 10 12 54
Bin 131 = 7 1 1 2 0 0 1 0 2
Bin 133 = 3 0 0 0 0 0 0 0 3
Bin 141 = 6 0 0 0 1 0 1 2 2
Bin 560 = 1 0 0 0 1 0 0 0 0
Bin 620 = 1 0 0 0 1 0 0 0 0
Bin 630 = 2 0 0 1 0 0 0 0 1
Bin 1250 = 1 0 0 0 0 0 1 0 0
Bin 1410 = 1 0 1 0 0 0 0 0 0
Bin 2004 = 1 0 0 0 0 0 0 1 0
Bin 2240 = 1 0 0 0 0 1 0 0 0
Bin 2247 = 1 0 0 1 0 0 0 0 0
Bin 2300 = 1 0 0 0 0 1 0 0 0
Bin 2309 = 1 0 0 0 1 0 0 0 0
Bin 2310 = 3 1 1 0 0 0 0 0 1
Bin 2602 = 1 0 0 0 1 0 0 0 0