Question

编写一种方法，从特定客户的帐户中提取资金并返回帐户余额。如果帐户上没有足够的钱，该方法将返回-1

方法的签名 - withdraw (String [] clients, int [] balances, String client, int amount)

    package Lesson5;

/**
 * Created by Ruslan on 12.06.2017.
 */
public class takeOffBalance {
    public static void main(String[] args) {
        String clients[] = {"John", "Pedro", "Valera", "Muchachos", "Vovan"};
        int [] balances = {1, 100, 3500, 222, 1234};
        System.out.println(withdraw(clients, balances, "Pedro", (int) 10000));
    }

    static int withdraw(String[] clients, int[] balances, String client, int amount) {

        int res = balances[findClient(clients, client)] - amount;
        return res >= 0 ? res : -1;

    }
    static int findClient (String [] clients, String client) {

        int clientIndex = 0;
        for (String name : clients) {
            if (name == client) {
                break;
            }
            clientIndex++;
        }
        return clientIndex;
    }


}

Answer 1

请尝试以下方法。你应该检查负数和余额。看起来有一个失败的负面测试。

static int withdraw(String[] clients, int[] balances, String client, int amount) {

    int index = findClient(clients, client);
    if (index == -1) // no client found
        return -1;
    // Negative balance, negative amount and insufficient credit.
    if(balances[index] < 0 || amount < 0 || balances[index] - amount < 0)
        return  -1;

    return balances[index] - amount;

}

static int findClient (String [] clients, String client) {

    int clientIndex = 0;
    for (String name : clients) {
        if (null != name && name.equals(client)) {
            break;
        }
        clientIndex++;
    }
    return -1; //no client found
}

Answer 2

您必须检查负数，如果帐户不存在，也不会检查案例。您需要添加所有这些验证才能使其正常工作。

错误＆＃34;＆lt; -1＆gt;但是：＆lt; 2147483647＆gt;＆＃34;。请告诉我，代码有什么问题？

2 个答案: