Question

需要帮助来解决我收到的错误：

$ INPUTFILE：

JKAFDHLFEWQR,AFLJHDJB7269367,100.000000,13/01/2017
AKDSNIVVXCOI,ASJDFGYQTWEYTRS,100.000000,08/06/2017
POASDJFHDHFJ,PAOSDFPOIK12311,98.500000,08/06/2017
NIUCIADFUASD,KLJFGUWYE89,100.150000,15/02/2017
NACSDHFIUDYD,ASDFMJKH124,100.150000,02/12/2015
QWERYEUYREOQ,JDFSJ62736J,100.150000,04/12/2015
UQER76786ADS,MCVKJDUAFIO,100.150000,01/02/2016
NMCXHJKSDH67,ZNKSOQ,10.000000,13/04/2016
MAOJI2637868,BNIISA,10.000000,04/04/2016
CMASDHFUIQE1,AMSTER,10.000000,04/04/2016
JSFHIEUWRYJF,POQERUANSHJKSHD,100.000000,19/12/2016
23KJDKH7SD67,MKOAUSDUIFOIUQW,100.000000,12/12/2016

预期结果:(空格+ 0 +空格+数组[0] +带有前导零的数组[2]的内容）

 0                   JKAFDHLFEWQR 0000000000000100.000000
 0                   AKDSNIVVXCOI 0000000000000100.000000
 0                   POASDJFHDHFJ 0000000000000098.500000
 0                   NIUCIADFUASD 0000000000000100.150000
 0                   NACSDHFIUDYD 0000000000000100.150000
 0                   QWERYEUYREOQ 0000000000000100.150000
 0                   UQER76786ADS 0000000000000010.000000
 0                   NMCXHJKSDH67 0000000000000010.000000
 0                   MAOJI2637868 0000000000000010.000000
 0                   CMASDHFUIQE1 0000000000000010.000000
 0                   JSFHIEUWRYJF 0000000000000100.000000
 0                   23KJDKH7SD67 0000000000000100.000000

我的代码：

gc $InputFile | ForEach-Object {

  $Value = $_ -split ','

  $Val2 = $Value[2] | % PadLeft 23 '0'

  $FileOut += $19spaces + $Value[0] + " " + $Val2 + "`n"

}

$FileOut.Split("`n") + $LastLine | Out-File $OutFile

$ LastLine在末尾添加一个尾随行：

 0                    0000000000000000.000000

代码完全按照我的需要提供了这些错误信息：

％：您无法在空值表达式上调用方法。在 C：\ Desktop \ test.ps1：92 char：23 + $ Val2 = $ Value [2] | ％PadLeft 23'0' + ~~~~~~~~~~~~~~~~ + CategoryInfo：InvalidArgument：（:) [ForEach-Object]，PSArgumen tException + FullyQualifiedErrorId：InvokeMethodOnNull，Microsoft.PowerShell.Commands .ForEachObjectCommand

有关如何修复此错误的任何想法吗？谢谢大家！

Answer 1

这个PowerShell单线程应该用

Import-csv和手动提供的标题H1..H4
-f format operator：

> import-csv .\input.txt -header H1,H2,H3,H4|%{" {0,-20}{1} {2}" -f 0,$_.H1,$_.H3.PadLeft(23,'0')}
 0                   JKAFDHLFEWQR 0000000000000100.000000
 0                   AKDSNIVVXCOI 0000000000000100.000000
 0                   POASDJFHDHFJ 0000000000000098.500000
 0                   NIUCIADFUASD 0000000000000100.150000
 0                   NACSDHFIUDYD 0000000000000100.150000
 0                   QWERYEUYREOQ 0000000000000100.150000
 0                   UQER76786ADS 0000000000000100.150000
 0                   NMCXHJKSDH67 0000000000000010.000000
 0                   MAOJI2637868 0000000000000010.000000
 0                   CMASDHFUIQE1 0000000000000010.000000
 0                   JSFHIEUWRYJF 0000000000000100.000000
 0                   23KJDKH7SD67 0000000000000100.000000

尾随空白行没有问题。

Answer 2

我能找到重现此问题的唯一方法是在$InputFile的内容中添加额外的行

要修复它，只需验证分割返回的内容不是$ null

$Value = $_ -split ','

if ($value -ne $null)
{
   $Val2 = $Value[2] | % PadLeft 23 '0'

   $FileOut += $19spaces + $Value[0] + " " + $Val2 + "`n"
}

Answer 3

无需将文本传递给PadLeft。

$Val2 = $Value[2].PadLeft(23, '0')

Powershell使用PadLeft方法X Null-Valued Expression

3 个答案: