URL更改但视图在React Router 4中没有变化

时间:2017-06-12 22:43:51

标签: reactjs redux react-router

我正在使用反应路由器4不对路由器3做出反应,所以我使用react-router-dom。我试图让this.props.history.push工作,但它所做的只是保持视图相同,但URL更改。

例如,我单击按钮,它调用一个只调用this.props.history.push('/ posts')的函数。网址从localhost:3000 / signin更改为localhost:3000 / posts。但我仍然在观察。

如果我点击刷新,它会重定向到帖子页面。我已经看了其他问题,那些人无论如何都无法去那里,即使他们刷新或进入网址并点击进入。

我会发布下面的代码,看看我做错了什么。另外我使用的是反应路由器v4而不是3.我不能使用browserHistory.push和v3使用的其他东西。

代码:

成分:

import React, { Component } from 'react';
import {Field, reduxForm} from 'redux-form';
import {connect} from 'react-redux';
import * as actions from '../../actions';
import {withRouter} from 'react-router';

class Signin extends Component {
  constructor(props) {
    super(props);

    this.onSubmit = this.onSubmit.bind(this);
  }

  renderField(field) {
    const { meta: {touched, error} } = field;
    const className = `form-group ${touched && error ? 'has-danger' : ''}`;

    return (
      <div className={className}>
        <label><strong>{field.label}:</strong></label>
        <input
          className="form-control"
          type={field.type}
          {...field.input}
        />
        <div className="text-help">
          { touched ? error : ''}
        </div>
      </div>
    )
  }

  onSubmit({email, password}) {
    // this.props.signinUser({email, password}, () => {
      this.props.history.push('/posts');
    // });
  }

  renderAlert() {
    if(this.props.errorMessage) {
      return (
        <div className="alert alert-danger">
          <strong>Oops</strong> {this.props.errorMessage}
        </div>
      )
    }
  }

  render() {
    const { handleSubmit } = this.props;

    return (
      <form onSubmit={handleSubmit(this.onSubmit)}>
        <Field
          label="Email"
          name="email"
          type="email"
          component={this.renderField}
        />
        <Field
          label="Password"
          name="password"
          type="password"
          component={this.renderField}
        />
        {this.renderAlert()}
        <button type="submit" className="btn btn-success">Sign In</button>
      </form>
    );
  }
}

function validate(values) {
  const errors = {};

  //Validate the inputs from values
  if(!values.email) {
    errors.email = "Enter an email!";
  }
  if(!values.password) {
    errors.password = "Enter a password!";
  }
  //If errors is empty, the form is fine to submit
  //If errors has any properties, redux form assumes form is invalid
  return errors;
}

function mapStateToProps(state) {
  return {
    errorMessage: state.auth.error
  };
}

export default reduxForm({
  validate,
  form: 'signin'
})(connect(mapStateToProps, actions)(withRouter(Signin)));

行动:

export function signinUser({email, password}, cb) {
  return function(dispatch) {
    axios.post(`${ROOT_URL}/signin`, {email, password})
      .then((response) => {
        dispatch({type: AUTH_USER});
        localStorage.setItem('token', response.data.token);

      })
      .then(() => cb())
      .catch((error) => {
        dispatch(authError(error.response.data.error));
      })
  }
}

2 个答案:

答案 0 :(得分:2)

我发现问题不在我发布的代码中,而是我在做我的路线。确保在路由时,您没有将路由嵌套为路径的组件。例如,我有:

const Routes = (
  <Provider store={store}>
    <BrowserRouter>
    <App />
    </BrowserRouter>
  </Provider>
)

这里我将App作为一个组件导入(或者它作为组件导出),我将它从组件更改为普通函数。为了更清楚,我将在下面放置旧代码和新代码:

旧:

class App extends React.Component {
 render() {
  return (
   <div>
    <Switch>
      <Route exact path='/' component={Home} />
      <Route path="/signin" component={RequireUnAuth(Signin)} />
      <Route path="/signout" component={Signout} />
      <Route path="/signup" component={Signup} />
      <Route path="/posts" component={Posts} />
    </Switch>
   </div>
  )
 }
}

新:

const App = () => (
   <div>
    <Switch>
      <Route exact path='/' component={Home} />
      <Route path="/signin" component={RequireUnAuth(Signin)} />
      <Route path="/signout" component={Signout} />
      <Route path="/signup" component={Signup} />
      <Route path="/posts" component={Posts} />
    </Switch>
   </div>
  )

这是正在导出的应用程序,一旦我切换到一个简单的功能而不是基于组件的类,一切正常。我没有必要进行硬刷新,我可以点回来然后返回,使用this.props.history.push重定向工作等...

答案 1 :(得分:0)

确保安装了最新版本的react-router-redux(https://github.com/reactjs/react-router-redux),并支持React Router 4。在package.json中:

"react-router-redux": "next"

接下来,按照有关将历史中间件添加到redux商店的说明进行操作。链接:https://github.com/reactjs/react-router-redux#what-if-i-want-to-issue-navigation-events-via-redux-actions

一旦安装了正确的软件包和中间件,就需要将reducer导入索引缩减器,例如:

import {combineReducers} from 'redux';
import {routerReducer} from 'react-router-redux';

const IndexReducer = combineReducers({
    router: routerReducer,
    //...other reducers go here
});

export default IndexReducer;

然后,在您想要发送它的任何地方导入push方法(例如actions.js):

import {push} from 'react-router-redux';

然后像这样使用它:

dispatch(push('/your/route/here'));