Question

对于我来说，检查一个字典中的值是否是来自另一个字典的列表值的子集的最pythonic方法是什么。到目前为止，我有以下代码但是，如果来自res的itemB＆＃39的值是valB，则代码是可以的。但如果值为valBA或valBB，则失败。

exp = dict(itemA = ['valA1', 'valA2'], itemB = ['valB', ['valBA', 'valBB']], itemC = ['valC1', 'valC2'])
res = dict(itemA = 'valA1', itemB = 'valBA', itemC = 'valC1')
for e, r in zip(sorted(exp), sorted(res)):
    if r == 'itemB':
        return any(res[r] in s for s in exp[e][0])
    else:
        return res[r] in exp[e]

Answer 1

不清楚你想要什么 - 列出哪些子集或子集值？此外，您不需要拉链 - 因为dict是一个无序集合，除非您可以提供明确的订单（您正在尝试排序）并且如果这两个指令不具备相同的数字和相同的命名键 - 它将失败。这样做要简单得多：

exp = dict(itemA=['valA1','valA2'],itemB=['valB',['valBA','valBB']],itemC=['valC1','valC2'])
res = dict(itemA='valA1',itemB='valBA',itemC='valC1')

subsets = [k for k, v in res.items() if v in exp.get(k, {})]
# ['itemC', 'itemA']

subset_values = [v for k, v in res.items() if v in exp.get(k, {})]
# ['valA1', 'valC1']

# to check if all subsets exist
all_subsets = all(v in exp.get(k, {}) for k, v in res.items())
# False

如果您需要检查两个级别，假设子级别是一个列表，您可以这样做：

subsets = []
for group, value in res.items():
    for subgroup in exp.get(group, []):
        if value == subgroup or (isinstance(subgroup, list) and value in subgroup):
            subsets.append(group)  # or append value if you're after that
            break

 # ['itemA', 'itemB', 'itemC']

 # or to check if all matched:
 all_subsets = len(subsets) == len(exp)
 # True

Answer 2

你可以试试这个：

exp = dict(itemA = ['valA1', 'valA2'], itemB = ['valB', ['valBA', 'valBB']], itemC = ['valC1', 'valC2'])
res = dict(itemA = 'valA1', itemB = 'valBA', itemC = 'valC1')

new_vals = [a for a, b in zip(res.values(), exp.values()) if a in b]

从一个字典检查值包含来自另一个字典

2 个答案: