Question

我正在使用照片共享扩展程序的iOS应用程序，处理图像并触发主要功能。

在Photo的应用程序的模拟器中，这很好用。我决定使用Photo的应用程序在设备上运行它也很棒，但是当我截屏并尝试从iOS 11的新“快速截图”分享时，扩展程序崩溃了，有什么想法吗？

扩展程序获取图像，将其发送到服务器，获取响应并显示该响应（所有内容都在扩展名中）。当我从快速截图访问时，Messenger和Snapchat共享扩展仍然有用，这让我很烦恼！

Xcode 9也没有给我任何来自共享扩展的日志。值得注意的是，我每次在设备上重新安装应用程序时都会使用我需要“信任”的开发者帐户。

代码：

// App Group keys

let suiteName = "group.suite.id"

override func viewDidLoad() {
    print("Styling views..")
    styleViews()
    print("Styled views")
    print("Adding notifications..")
    addNotifications()
    print("Added notifications")
    print("Fetching image..")
    fetchSharedImage()
}

func styleViews(){
    // Set up main view
    mainView.layer.cornerRadius = 8
    mainShadowView.addShadow()

    // Set up views and buttons
    // Code hidden, applies shadows etc.

    // Code hidden, moves constraints of a view
}

func addNotifications(){
    // Helps views tell their parent (this view controller) to navigate to another form
    NotificationCenter.default.addObserver(forName: NotificationDisplayFetchedLink, object: nil, queue: nil){ notification in
        // Handles user info in lambda block
        guard let userInfo = notification.userInfo,
            let link = userInfo["link"] as? String
            else {
                print("No userInfo found in notification")
                return
            }
        self.displayResult(with: link)
    }
}

func fetchSharedImage(){
    // Make sure we have a valid extension item
    if let content = extensionContext!.inputItems[0] as? NSExtensionItem {
        let contentType = kUTTypeImage as String

        // Verify the provider is valid
        if let contents = content.attachments as? [NSItemProvider] {
            // look for images
            for attachment in contents {
                if attachment.hasItemConformingToTypeIdentifier(contentType) {
                    attachment.loadItem(forTypeIdentifier: contentType, options: nil) { data, error in
                        let url = data as! URL
                        if let imageData = try? Data(contentsOf: url) {
                            self.selectedImage = UIImage(data: imageData)

                            DispatchQueue.main.async {
                                self.selectedImageView.layer.cornerRadius = 8
                                self.selectedImageView.image = self.selectedImage
                            }
                            self.makeWebRequest()

                        }
                    }
                }
            }
        }
    }
}

func makeWebRequest(){
    let url = URL(string: "url.json")
    let task = URLSession.shared.dataTask(with: url!) { data, response, error in
        guard error == nil else {
            return
        }
        guard let data = data else {
            // Data is empty
            return
        }

        let json = try! JSONSerialization.jsonObject(with: data, options: []) as! NSDictionary
        guard let dict = json as? [String:Any] else { return }
        let item = dict["item"]
        guard let itemData = item as? [[String:Any]] else { return }
        let link = itemData[0]["url"]
        NotificationCenter.default.post(name: NotificationDisplayFetchedLink, object: nil, userInfo: [link: link!])
    }
    task.resume()
}

编辑：

所以解决方案（正如Owen Zhao所说）是iOS 11屏幕截图编辑器返回UIImage，而像Photos这样的应用程序会返回URL。

我优雅地处理这个问题的解决办法是将UIImage或URL转换为UIImage到iOS临时目录（3天后删除），然后将该目录中图像的URL保存到共享扩展名。

Answer 1

let url = data as! URL if let imageData = try? Data(contentsOf: url) {

问题是因为此处的数据不是网址。它是一个“public.image”，尝试转换为UIImage而不是Data。

Answer 2

在Objective C中您可以将以下代码用于共享为屏幕截图的图像。屏幕截图的扩展名为.png，请使用 public.png 代替 public.jpeg

if ([itemProvider hasItemConformingToTypeIdentifier:@"public.png"]){
            [itemProvider loadItemForTypeIdentifier:@"public.png" options:nil completionHandler: ^(id<NSSecureCoding> item, NSError *error) {
                dispatch_async(dispatch_get_main_queue(), ^{
                    NSData *imgData;
                    if([(NSObject*)item isKindOfClass:[NSURL class]]) {
                        imgData = [NSData dataWithContentsOfURL:(NSURL*)item];
                    }
                    if([(NSObject*)item isKindOfClass:[UIImage class]]) {
                        imgData = UIImagePNGRepresentation((UIImage*)item);
                    }
 UIImage *image=[UIImage imageWithData:imgData];
});

            }];

从iOS 11分享时，iOS Share Extension崩溃

2 个答案: