我使用Triple DES进行加密/解密,但不知怎的,它给了我以上异常,我尝试了相关答案中提到的其他方法,但我被卡住了。我是密码学和相应的java库的新手。
private static byte[] Key = new byte[] {
0x42, 0x45, 0x49, 0x30, 0x12, 0x22, 0x35, 0x48, 0x33, 0x24, 0x28, 0x51,
0x48, 0x24, 0x30, 0x21, 0x44, 0x31, 0x14, 0x19, 0x45, 0x34, 0x47, 0x25 };
Cipher c;
public EncryptionHelper() throws Exception {
// byte[] key_hash = (Key).toString().getBytes("UTF-8");
// key_hash = Arrays.copyOf(key_hash, 32);
SecretKey key = new SecretKeySpec(Key, 0, Key.length, "DESede");
c = Cipher.getInstance("DESede/ECB/PKCS5Padding");
c.init(Cipher.ENCRYPT_MODE, key);
}
public String Encrypt(String S) throws Exception {
byte[] base64EncryptedText = S.getBytes("UTF-8");
byte EncryptedText[] = c.doFinal(base64EncryptedText, 0, base64EncryptedText.length);
return new String(EncryptedText);
}
public String Decrypt(String S) throws Exception {
Cipher c2 = null;
// byte[] key_hash = (Key).toString().getBytes("UTF-8");
// key_hash = Arrays.copyOf(key_hash, 24);
SecretKey key = new SecretKeySpec(Key,0, Key.length, "DESede");
c2 = Cipher.getInstance("DESede/ECB/PKCS5Padding");
c2.init(Cipher.DECRYPT_MODE, key);
byte[] base64EncryptedText = Base64.getEncoder().encode(S.getBytes());
byte[] textDecrypted = c2.doFinal(base64EncryptedText, 0, base64EncryptedText.length);
return new String(textDecrypted, "UTF-8");
}
编辑:
最后通过解决方案,我只是错放了组件,也指定了核心逻辑。
public class EncryptionHelper {
private static byte[] Key = new byte[] {
0x42, 0x45, 0x49, 0x30, 0x12, 0x22, 0x35, 0x48, 0x33, 0x24, 0x28, 0x51,
0x48, 0x24, 0x30, 0x21, 0x44, 0x31, 0x14, 0x19, 0x45, 0x34, 0x47, 0x25 };
static Cipher c;
public EncryptionHelper() throws Exception {
// byte[] key_hash = (Key).toString().getBytes("UTF-8");
// key_hash = Arrays.copyOf(key_hash, 32);
SecretKey key = new SecretKeySpec(Key, 0, Key.length, "DESede");
c = Cipher.getInstance("DESede/ECB/PKCS5Padding");
c.init(Cipher.ENCRYPT_MODE, key);
}
public static String Encrypt(String S) throws Exception {
byte[] base64EncryptedText = S.getBytes("UTF-8");
byte EncryptedText[] = c.doFinal(base64EncryptedText, 0, base64EncryptedText.length);
return new String(Base64.getEncoder().encode(EncryptedText));
}
// LOGIC:
// for encryption: string -> utf-8 byte array,
// encrypt and return a base 64 encoded string
// for decryption: String -> base64 -> decode base 64 array,
// decrypt and return utf-8 string
public static String Decrypt(String S) throws Exception {
Cipher c2 = null;
// byte[] key_hash = (Key).toString().getBytes("UTF-8");
// key_hash = Arrays.copyOf(key_hash, 24);
SecretKey key = new SecretKeySpec(Key, "DESede");
c2 = Cipher.getInstance("DESede/ECB/PKCS5Padding");
c2.init(Cipher.DECRYPT_MODE, key);
byte[] base64EncryptedText = Base64.getDecoder().decode(S.getBytes());
byte[] textDecrypted = c2.doFinal(base64EncryptedText, 0, base64EncryptedText.length);
return new String(textDecrypted, "UTF-8");
}
答案 0 :(得分:1)
尽管您的变量上有名称,但您无法在Encrypt
方法中对加密结果进行base64编码。因此,当您将其转换为String时,您会获得垃圾,当您在Decrypt
方法中对该垃圾进行base64解码时,您将获得垃圾 2 。
答案 1 :(得分:0)
你是base64解码然后解密,但你没有加密,然后是base64编码。