Question

使用更新的代码我试图绑定支付和网站之间的关系，但似乎分组不工作。而且我得到了很多重复的结果。

已更新：

$this->Website->unBindModel(array('hasMany' => array('User')));
$this->Website->bindModel(array(
                                'hasMany' => array(
                                    'Payment' => array(
                                        'className' => 'Payment',
                                        'foreignKey' => 'website_id',
                                        'fields' => array(
                                            'Payment.id',
                                            'Payment.website_id',
                                            'Payment.created',
                                            'Payment.user_id',
                                            'Payment.is_get_invoice'
                                        ) ,
                                        'conditions' => array(
                                            'Payment.website_id <>' => '0',
                                            'Payment.is_get_invoice' => '0'
                                        ),
                                        'order' => array(
                                            'Payment.id DESC'
                                        ),
                                        'group' => array(
                                            'Payment.website_id' //Its not working
                                        )
                                    )
                                )
                            )
                        );


$this->Website->recursive = 1;
$webPayments = $this->Website->find('all', array('fields' => array('Website.id'),'contain' => array('Payment')));

旧：

我正在尝试绑定和取消绑定模型运行时。但它给了我错误。甚至协会都没有工作。

$this->Website->unBindModel(array(
    'hasMany' => array(
        'User'
    )
));
$this->Website->bindModel(array(
    'hasMany' => array(
        'Payment' => array(
            'className' => 'Payment',
            'foreignKey' => 'website_id'
        )
    )
));
$this->Website->recursive = 1;
$webPayments = $this->Website->find('all', array(
    'fields' => array(
        'Website.id',
        'Payment.id',
        'Payment.website_id',
        'Payment.created',
        'Payment.user_id'
    ) ,
    'conditions' => array(
        'Payment.website_id <>' => '0',
        'Payment.is_get_invoice' => '0'
    ) ,
    'order' => array(
        'Payment.id DESC',
        'group' => array(
            'Payment.website_id'
        )
    )
));

pr($webPayments);

错误：

Columnnotfound：“字段列表”中的1054 Unknowncolumn'Repport.id'

SELECT`Website` . `id`, `Payment` . `id`, `Payment` . `website_id`, `Payment` . `created`, `Payment` . `user_id`, FROM`websites` AS `Website`WHERE`Payment` . `website_id` <> 0 AND `Payment` . `is_get_invoice` = '0' AND `Payment` . `created` > '2017-04-13 07:07:54' GROUPBY `Payment` . `website_id` ORDERBY `Payment` . `id` DESC

Answer 1

尝试使用像这样的包含：

$webPayments = $this->Website->find('all', array(
    'fields' => array(
        'Website.id',       
    ),
    'contain' => array(
        'Payment' => array(
            'fields' => array(
                'Payment.id',
                'Payment.website_id',
                'Payment.created',
                'Payment.user_id'
            ),
            'conditions' => array(
                'Payment.website_id <>' => '0',
                'Payment.is_get_invoice' => '0'
            ),
            'order' => array(
                'Payment.id DESC',
                'group' => array(
                    'Payment.website_id'
                )
            )
        )
    )
));

https://book.cakephp.org/2.0/en/core-libraries/behaviors/containable.html

Answer 2

您的模型是否已正确宣布关联？你应该

class Payment extends AppModel {
    var $name = 'Payment';
    public $actAs = array('Containable');

public $belongsTo = array (
    'Website' => array(
        'className' => 'Website',
        'foreignKey' => 'website_id'
    )
)
[...]
}

class Website extends AppModel {
    var $name 'Website';
    public $actAs = array('Containable');

    public $hasMany = array(
        'Payment' => array(
             'className'=>'Payment',
             'order' => 'Payment.id DESC'
         )
    )
[...]
}

我发现在模型中尽可能低地声明事物确实比尝试使用查询动态执行它更好。如果在模型本身中正确声明了关联，则不应该使用dork与绑定/解除绑定..

Answer 3

hasMany关联不支持group by密钥。

在这种特殊情况下，你试图通过错误使用group来实现的只是返回一个结果。请注意，使用支持的limit密钥可以实现相同的功能。

代码如下：

$this->Website->unBindModel(array('hasMany' => array('User')));
$this->Website->bindModel(array(
                            'hasMany' => array(
                                'Payment' => array(
                                    'className' => 'Payment',
                                    'foreignKey' => 'website_id',
                                    'fields' => array(
                                        'Payment.id',
                                        'Payment.website_id',
                                        'Payment.created',
                                        'Payment.user_id',
                                        'Payment.is_get_invoice'
                                    ) ,
                                    'conditions' => array(
                                        'Payment.website_id <>' => '0',
                                        'Payment.is_get_invoice' => '0'
                                    ),
                                    'order' => array(
                                        'Payment.id DESC'
                                    ),
                                    'limit' => 1
                                    )
                                )
                            )
                        )
                    );

参考

CakePHP 2.x hasMany Association

Cakephp运行时bindmodel associaton group by无效

3 个答案: