Question

我试图通过命名函数来避免回调地狱，但我无法请求传递一个不属于原始范围的对象？父方法。

这是我正在尝试优化的工作代码：

//req exists, as this is inside an Express route handler 
charge.create({
    amount: req.body.amount
    //...
}, function(err, createdCharge) {
      console.log('Purchased: '+req.body.product);
      res.send('Success');
}

当我尝试模块化我的代码时，我不确定如何传递req对象，因为charge.create方法是我没有做的，所以我不能让它接受任何其他参数：< / p>

charge.create({
   amount: req.body.amount
   //...
}, confirmCharge);

function confirmCharge(err, createdCharge) {
      console.log('Purchased: '+req.body.product); //req doesn't exist!
}

Answer 1

charge.create({
   amount: req.body.amount
   //...
}, confirmCharge(req));

function confirmCharge(req) {
      console.log('Purchased: '+req.body.product); //req exists!
}

如何在回调函数中传递原始请求？

1 个答案: