Question

我正在网上寻找帮助我解决这个问题的东西。我学会了如何制作一个arrayList，但我想知道如何让它成为可接受的用户输入。我的意思是我希望用户输入他的号码。这就是我所拥有的：

org.openqa.selenium.WebDriverException: Could not convert screenshot to base64 - 
Error: Unable to load canvas into base64 string - 
[Exception... "Failure"  nsresult: "0x80004005 (NS_ERROR_FAILURE)"  
location: "JS frame :: file:///C:/Users/c38151/AppData/Local/Temp/anonymous7393315997897601641webdriver-profile/extensions/fxdriver@googlecode.com/components/driver-component.js :: fxdriver.screenshot.toBase64 :: line 10440"  data: no]
Command duration or timeout: 1.13 seconds
Build info: version: '2.53.0', 
revision: '35ae25b1534ae328c771e0856c93e187490ca824', 
time: '2016-03-15 10:43:46'
System info: host: 'W7E1384109', ip: '172.26.31.114', 
os.name: 'Windows 7', 
os.arch: 'amd64', 
os.version: '6.1', 
java.version: '1.8.0_74'
Driver info: org.openqa.selenium.firefox.FirefoxDriver
Capabilities [{applicationCacheEnabled=true, rotatable=false, handlesAlerts=true, databaseEnabled=true, version=45.2.0, platform=WINDOWS, nativeEvents=false, acceptSslCerts=true, webStorageEnabled=true, locationContextEnabled=true, browserName=firefox, takesScreenshot=true, javascriptEnabled=true, cssSelectorsEnabled=true}]
Session ID: e48040a1-37c2-4767-a46f-acaf697dc8c4

我现在拥有的是我放在那里的数字。非常感谢任何帮助。

提前致谢。

Answer 1

EndPoint = "https://us.api.concursolutions.com/oauth2/v0/otp"
Payload = "client_id=" & consumerKey & "&client_secret=" & consumerSecret & "&channel_handle=" & Email & "&channel_type=email"
Payload = Payload & "&link=" & link & "&name=" & name & "&company=" & company
Dim xmlhttp
Set xmlhttp = Createobject("MSXML2.ServerXMLHTTP.6.0")
'Get error message with or without the next 3 lines
XMLhttp.setOption(2) = 13056
strCert = "Friendly Name"
XMLhttp.setOption(3)= "LOCAL_MACHINE\My\" & strCert
XMLhttp.Open "POST",EndPoint,false    
XMLhttp.setRequestHeader "User-Agent","HTTP/1.1"
XMLhttp.setRequestHeader "Content-Type", "application/x-www-form-urlencoded; charset=utf-8"
XMLhttp.setRequestHeader "Accept", "application/json"
XMLhttp.setRequestHeader "Host", "us.api.concursolutions.com"
XMLhttp.setRequestHeader "Connection", "close"
XMLhttp.setRequestHeader "Content-Length", "437"
XMLhttp.send Payload

Answer 2

这两行代码是将用户输入到ArrayList中所必需的：

int n = input.nextInt();
myList.add(n);

所以完整的代码会显示为：

public class MyClass {     
    public static void main(String[] args) {    
        Scanner input=new Scanner(System.in);    
        ArrayList<Integer> myList=new ArrayList<Integer>(10);    
        System.out.println("Enter your number:");
        int n = input.nextInt();
        myList.add(n);
        myList.add(416355);    
        myList.add(21212);    
        for(int x : myList)    
            System.out.println(x);    
        System.out.println("Size="+myList.size());    

    } 
  }

您可能会发现这有用：How can I get the user input in Java?

Answer 3

    import java.util.ArrayList;
    import java.util.Scanner;

    public class MyClass {
        public static void main(String[] args) {
            Scanner input = new Scanner(System.in);
            ArrayList<Integer> myList = new ArrayList<Integer>(10);

            int totalNumbers = 10;
            for (int i = 0; i < totalNumbers; i++) {
                System.out.println("ENTER Element to add into list");
                Scanner element = new Scanner(System.in);
                int ele = (element .nextInt());
                myList.add(ele);
            }
            for (int x : myList)
                System.out.println(x);
            System.out.println("Size=" + myList.size());

        }
    }
So the full code would read:

Answer 4

据我所知，您希望捕获用户数据并将其保存到数组中;对于每个输入元素，您需要创建一个变量：

import java.util.ArrayList;
import java.util.Scanner;

public class MyClass {    
    public static void main(String[] args) {        
        ArrayList<Integer> myList=new ArrayList<Integer>(10);    enter code here
        System.out.println("Enter your number:");   
        Scanner input=new Scanner(System.in);
        int a = input.nextInt();
        int b = input.nextInt();
        myList.add(a);
        myList.add(b);
        for(int x : myList)    
            System.out.println(x);    
        System.out.println("Size="+myList.size());    

    }
  }

Answer 5

import java.util.ArrayList;
import java.util.Scanner;

public class Average
{

   public static void main(String[] args)
   {
      ArrayList<Double> numbers = new ArrayList<Double>();

      Scanner in = new Scanner(System.in);
      System.out.println("Please enter a list of numbers: ");

      while (in.hasNextDouble())
      {
         double input = in.nextDouble();
         numbers.add(input);
      }

      if (numbers.size() == 0)
      {
         System.out.println("No average.");

      } 

      else
      {
         double total = 0;
         for (double element : numbers)
         {
            total = total + element;
         }
         double average = total / numbers.size();
         System.out.println("The average is: " + average);

      }
   }

我试图在arraylist中使用用户输入

5 个答案: