防止犀牛在python中退一步

Question

我试图在python中为rhino创建一个步进函数， 该函数应该在随机方向上迈出一步，而不是向后退。 我如何防止退后？

import rhinoscriptsyntax as rs
import random as r
r.seed(seed)



class Walker:

def __init__(self):
    self.x = 0
    self.y = 0


def point(self):
    shape = rs.AddPoint(self.x, self.y, 0)
    return shape

def step(self):
    choice = r.randint(0,3)
        choice = r.randint(1,3)
    if (choice == 0):
        self.x = self.x + r.choice(uList)
    elif (choice == 1):
        self.x = self.x - r.choice(uList)
    elif (choice == 2):
        self.y = self.y + r.choice(uList)
    else:
        self.y = self.y - r.choice(uList)

uList = [8,11,14]

w = Walker()


pList = []
for t in range(time):
w.step()
pList.append(w.point())

for t-1 in range(time):

a = pList

Answer 1

这一行：

choice = r.randint(0,3)

随机选择4个方向中的一个。但如果你不想倒退，那么你只需要向前，向左和向右。因此，请将参数更改为randint()，以便它只从3个可能的数字中选择，避免与您正在调用向后的方向对应的数字，无论哪个。