尝试使用辅助函数计算文本文件中的音节数时出错[Python]

Question

我对编程很陌生，目前正在尝试学习Python。我的目标是使用网页抓取，或者更具体地说是BeautifulSoup来获取在dictionary.com上的一个单词的音节并计算有多少音节。通过这个，我想使用该函数来计算大文本文件中有多少个音节。但是，当我尝试在函数“syllables”中实现辅助函数“count_syllables”时，我似乎一直试图找出我的代码出错的地方。以下是我的代码和错误消息的一部分：

def count_syllables(keyword):
    url = 'http://dictionary.com/browse/{}'.format(keyword)
    web_object = requests.get(url)
    text = web_object.text
    text = text.encode('utf-8')
    soup = BeautifulSoup(text, 'html.parser')
    div = [div for div in soup.find_all('div', {'class': "waypoint-wrapper header-row header-first-row"})]
    span = [div.find(name='span') for div in div]
    span = span[0]['data-syllable']
    strip_mid = span.replace('·', ' ')
    syl = len(strip_mid.split())

    return syl

grab_text = ['airplane.txt', 'sea.txt']
for file in grab_text:
    with open(os.path.join("bigfile", file), "r") as infile:
        all_text = infile.readlines()
        entry = ''.join(all_text)

        def syllables():
            split_words = entry.split()
            print('HERE ARE THE NUMBER OF SYLLABLES IN', file.upper())
            for words in split_words:
                words = count_syllables(split_words)
                add_words = sum(words)
                return add_words

        print(syllables())

错误：IndexError：列表索引超出范围

Answer 1

看起来有时候

span = span[0]['data-syllable']

span将是一个空列表，因此您无法将其编入索引。

您需要实施某种检查。您可以执行try-catch，if语句或其他内容。