Question

我希望在以下文件中使用Linux中的ed编辑器在一行中进行多次替换：

#device     device      mount       FS  fsck    mount   mount
#to mount   to fsck     point       type    pass    at boot options
#
#/dev/dsk/c0d0s2 /dev/rdsk/c0d0s2 /usr      ufs 1   yes -
fd  -   /dev/fd fd  -   no  -
/proc   -   /proc   proc    -   no  -
/dev/dsk/c0d0s3 -   -   swap    -   no  -
/dev/dsk/c0d0s0 /dev/rdsk/c0d0s0    /   ufs 1   no  -
/dev/dsk/c0d0s4 /dev/rdsk/c0d0s4    /usr    ufs 1   no  -
/dev/dsk/c0d0s1 /dev/rdsk/c0d0s1    /var    ufs 1   yes -
/dev/dsk/c0d0s7 /dev/rdsk/c0d0s7    /export ufs 2   yes -
/dev/dsk/c0d0s5 /dev/rdsk/c0d0s5    /usr/informix   ufs 2   yes -
swap    -   /tmp    tmpfs   -   yes -

我想在 / dev / ....中将所有“c0”与“c1”交换....

以下是我的正则表达式：1,\$s/$\/dev.*$$c0$$d0s.*$/\1c1\3/g，其结果为

   #device      device      mount       FS  fsck    mount   mount
    #to mount   to fsck     point       type    pass    at boot options
    #
    #/dev/dsk/c0d0s2 /dev/rdsk/c1d0s2 /usr      ufs 1   yes -
    fd  -   /dev/fd fd  -   no  -
    /proc   -   /proc   proc    -   no  -
    /dev/dsk/c1d0s3 -   -   swap    -   no  -
    /dev/dsk/c0d0s0 /dev/rdsk/c1d0s0    /   ufs 1   no  -
    /dev/dsk/c0d0s4 /dev/rdsk/c1d0s4    /usr    ufs 1   no  -
    /dev/dsk/c0d0s1 /dev/rdsk/c1d0s1    /var    ufs 1   yes -
    /dev/dsk/c0d0s7 /dev/rdsk/c1d0s7    /export ufs 2   yes -
    /dev/dsk/c0d0s5 /dev/rdsk/c1d0s5    /usr/informix   ufs 2   yes -
    swap    -   /tmp    tmpfs   -   yes -

然而，这个长正则表达式：
1,\$s/$\/dev.*$$c0$$d0s.*$$\/dev.*$$c0$$d0s.*$/\1c1\3\4c1\6/g会产生这样的结果：

#device     device      mount       FS  fsck    mount   mount
#to mount   to fsck     point       type    pass    at boot options
#
#/dev/dsk/c1d0s2 /dev/rdsk/c1d0s2 /usr      ufs 1   yes -
fd  -   /dev/fd fd  -   no  -
/proc   -   /proc   proc    -   no  -
/dev/dsk/c0d0s3 -   -   swap    -   no  -
/dev/dsk/c1d0s0 /dev/rdsk/c1d0s0    /   ufs 1   no  -
/dev/dsk/c1d0s4 /dev/rdsk/c1d0s4    /usr    ufs 1   no  -
/dev/dsk/c1d0s1 /dev/rdsk/c1d0s1    /var    ufs 1   yes -
/dev/dsk/c1d0s7 /dev/rdsk/c1d0s7    /export ufs 2   yes -
/dev/dsk/c1d0s5 /dev/rdsk/c1d0s5    /usr/informix   ufs 2   yes -
swap    -   /tmp    tmpfs   -   yes -

将第一个“c0”保留为“c0”，因为搜索字符串找不到它

所以我得到了一个文件，我在一行中获得了多个搜索结果，但它只替换了一个实例。我知道“全局”-Flag在文件的第一步中运行并标记匹配的行。我希望我知道导致这个问题的原因，但是我没有足够的经验知道怎么解决它干杯为你提供帮助

Answer 1

您可以使用g命令搜索带有dev字符串的行，然后使用s（替换）命令和g（全局）标记全局替换：

g/\/dev/s/c0/c1/g

给你预期的结果：

#device     device      mount       FS  fsck    mount   mount
#to mount   to fsck     point       type    pass    at boot options
#
#/dev/dsk/c1d0s2 /dev/rdsk/c1d0s2 /usr      ufs 1   yes -
fd  -   /dev/fd fd  -   no  -
/proc   -   /proc   proc    -   no  -
/dev/dsk/c1d0s3 -   -   swap    -   no  -
/dev/dsk/c1d0s0 /dev/rdsk/c1d0s0    /   ufs 1   no  -
/dev/dsk/c1d0s4 /dev/rdsk/c1d0s4    /usr    ufs 1   no  -
/dev/dsk/c1d0s1 /dev/rdsk/c1d0s1    /var    ufs 1   yes -
/dev/dsk/c1d0s7 /dev/rdsk/c1d0s7    /export ufs 2   yes -
/dev/dsk/c1d0s5 /dev/rdsk/c1d0s5    /usr/informix   ufs 2   yes -
swap    -   /tmp    tmpfs   -   yes -

Linux ed编辑器在一行中多次搜索/替换

1 个答案: