Question

我有一个流需要跳过而bool是真的。

但是，当bool设置为false时，我需要应用跳过时丢失的最后一个流值。

.site-inner, .wrap {
    margin: 0 auto;
    max-width: 1100px;
    }


   .cubutton {
    display: block;
    box-sizing: border-box;
    border-radius: 99999px;
    background-color: #44ace8;
    color: #fff;
    cursor: pointer;
    font-family: 'Quicksand', sans-serif;
    font-size: 20px;
    font-size: 2.0rem;
    font-weight: 700;
    text-align: center;
    letter-spacing: 1px;
    padding: 20px 40px 20px 40px;
    margin-left: auto;
    margin-right: auto;
    margin-top: 25px;
    margin-bottom: 25px;
    width: 100%;
    text-transform: uppercase;
    -webkit-font-smoothing: antialiased;
    -webkit-box-shadow: 4px 4px 5px 0px rgba(50, 50, 50, 0.75);
    -moz-box-shadow: 4px 4px 5px 0px rgba(50, 50, 50, 0.75);
    box-shadow: 4px 4px 5px 0px rgba(50, 50, 50, 0.75);
    -webkit-transition: all 0.1s ease-in-out;
    -moz-transition: all 0.1s ease-in-out;
    -ms-transition: all 0.1s ease-in-out;
    -o-transition: all 0.1s ease-in-out;
    transition: all 0.1s ease-in-out;
}

Answer 1

使用多播共享开始和其余值。 pairwise to pairt prev和next value and concat to begin start and the rest。

 Rx.Observable.interval(500)
   .multicast(new Rx.Subject(), shared => {
      let start$ = shared
                  .pairwise()
                  .skipWhile((x)=>x[1]<5) // this is the condition to skip
                  .first()         
                  .switchMap(el=>Rx.Observable.concat(Rx.Observable.of(el[0]), 
                                 Rx.Observable.of(el[1])));
      return Rx.Observable.concat(start$, shared);
}).subscribe(x=>console.log(x));

RxJS5 - skipWhile但在跳过时保留值？

1 个答案: