我有一个PHP文件和其他JavaScript。在JavaScript中,我将变量与文件存在的位置传递,但在PHP端没有识别并且没有正确下载文件。
JavaScript代码:
var nameFile = oEvent.getParameters().listItem.getTitle();
var directory = "C:/xampp/htdocsui5launchpad/WebContent/documents/";
window.location =directory;
$.ajax({
url: 'http://localhost/ui5launchpad/WebContent/php/downloadPDF.php',
type: 'POST',
datatype: "json",
data: { album: nameFile },
success: function (response, data, xhr) {
window.location = 'http://localhost/ui5launchpad/WebContent/php/downloadPDF.php';
},
error: function (response) {
console.log("Error in PHP, downloadPDF.php ");
}
});
PHP代码:
if(isset($_POST["album"])){
$name = $_POST["album"];
}
$dir = "C:/xampp/htdocs/ui5launchpad/WebContent/documents/";
$file = $dir . $name;
if( isset($file)) {
//echo $file;
if (file_exists($file)) {
//echo $file;
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename="'.basename($file).'"');
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
readfile($file);
exit;
}
}
请帮帮我吗?
由于
答案 0 :(得分:0)
您无需使用ajax下载文件。只需将文件直接链接到浏览器即可。
在link标签中输入如下属性:
<a href="http://example.com/file.pdf" download>Download</a>