我有3个组合框,请参阅以下代码
<select name="option1" id="option1" onchange="populate(this.id,'option2','option3','option4')">
<option value=""></option>
<option value="1">public</option>
<option value="2">private</option>
</select><br>
<select name="option2" id="option2" onchange="populate('option1',this.id,'option3','option4')">
<option value=""></option>
<option value="1">primary</option>
<option value="2">secondary</option>
</select><br>
<select name="option3" id="option3" onchange="populate('option1','option2',this.id,'option4')">
<option value=""></option>
<option value="1">office1</option>
<option value="2">office2</option>
<option value="3">office3</option>
<option value="4">office4</option>
</select><br>
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我需要使用前3个组合框中的参数从mysql表中获取值,以填充最后一个组合框。所以这是我的SQL查询:
$sql = "SELECT * FROM `schools` WHERE `kind_of_education` LIKE '.$option1.' `AND `class_type` LIKE '.$option2.' AND `office` LIKE '.$option3.";`
我希望像这段代码一样:
<!DOCTYPE html>
<html>
<head>
<script>
function populate(s1,s2){
var s1 = document.getElementById(s1);
var s2 = document.getElementById(s2);
s2.innerHTML = "";
if(s1.value == "Chevy"){
var optionArray = ["|","camaro|Camaro","corvette|Corvette","impala|Impala"];
} else if(s1.value == "Dodge"){
var optionArray = ["|","avenger|Avenger","challenger|Challenger","charger|Charger"];
} else if(s1.value == "Ford"){
var optionArray = ["|","mustang|Mustang","shelby|Shelby"];
}
for(var option in optionArray){
var pair = optionArray[option].split("|");
var newOption = document.createElement("option");
newOption.value = pair[0];
newOption.innerHTML = pair[1];
s2.options.add(newOption);
}
}
</script>
</head>
<body>
<h2>Choose Your Car</h2>
<hr />
Choose Car Make:
<select id="slct1" name="slct1" onchange="populate(this.id,'slct2')">
<option value=""></option>
<option value="Chevy">Chevy</option>
<option value="Dodge">Dodge</option>
<option value="Ford">Ford</option>
</select>
<hr />
Choose Car Model:
<select id="slct2" name="slct2"></select>
<hr />
</body>
</html>
&#13;
答案 0 :(得分:0)
你必须在php中使用你的$ sql变量来调用你的数据库,然后代替列出平面选项,在你的查询结果上做一个foreach循环来填充选项的值
答案 1 :(得分:0)
我试过这段代码,但它有许多不起之处:
<script>
function populate(op1,op2,op3,op4){
var op1 = document.getElementById(op1).value.toString();
var op2 = document.getElementById(op2).value.toString();
var op3 = document.getElementById(op3).value.toString();
var op4 = document.getElementById(op4).value.toString();
op4.innerHTML = "";
<?php
$op1="<script>op1.value.toString();</script>";
$op2="<script>op2</script>";
$op3="<script>op3</script>";
$conn = mysql_connect('localhost','yaser95','123456789');
mysql_select_db('students',$conn);
$query = "SELECT `school_id`, `school_name` FROM `schools` WHERE `kind_of_education`=$op1 and `class_type`=1 and `office`=1 ORDER BY `school_name`";
$sSQL= 'SET CHARACTER SET utf8';
$result = mysql_query($sSQL,$conn) or die ('Can\'t charset in DataBase');
$result = mysql_query($query,$conn);
$selectbox='<select name=\'schools\'>';
while ($row = mysql_fetch_assoc($result)) {
"<script>
var newOption = document.createElement("option");
newOption.value =" $row['school_id']
"newOption.innerHTML =" $row['school_name']
"s2.options.add(newOption);
</script>"
}
?>
}
</script>