首先,我想对发布存在的类似帖子表示歉意。但由于我无法解决它,因此我发布了它。
我有一个有线字符串模式(mongo输出),我需要将其转换为仅值。
"_id" : ObjectId("59280d9b95385c78b73252e4"), "categorySetId" : NumberLong(1100000041), "categorySetName" : "PROD GROUP", "serviceableProductFlag" : "N", "categoryId" : NumberLong(1053), "pid" : "800-319-03", "productFamily" : "PP", "productType" : "SEATS", "subGroup" : "PP SER", "description" : "^AY,EECH, NG-C", "inventoryItemId" : NumberLong(200699), "itemStatusMfg" : "S-INTV", "organizationIdMfg" : NumberLong(90000), "src" : "orcl", "syncedOn" : NumberLong("1495797136138"), "CreationDate" : ISODate("2017-05-26T11:12:16.138Z"), "CreatedBy" : "tool", "LastUpdatedDate" : ISODate("2017-05-26T11:12:16.138Z"), "LastUpdatedBy" : "tool", "itemFamilyDesc" : "PP FAMILY", "itemFamilyGroupId" : 750, "itemFamilyGroupName" : "PP SERIES PRODUCTS"
我想输出
59280d9b95385c78b73252e4,1100000041,PROD GROUP,N,1053,800-319-03,PP, SEATS,PP SER ,'^AY,EECH, NG-C', 200699,S-INTV,90000,orcl,1495797136138,2017-05-26T11:12:16.138Z,tool,2017-05-26T11:12:16.138Z,tool,PP FAMILY,750,PP SERIES PRODUCTS
我尝试了各种sed和awk,但我无法实现它。
sed 's/"[^"]*://g' text.txt
sed 's/"[^:]*://g' text.txt
有人可以帮我吗?
非常感谢提前。
答案 0 :(得分:1)
awk 解决方案:
awk -F': +|, *"' '{ r=""; for(i=2;i<=NF;i+=2) {
gsub(/^ *([^(]+\()?|"|\)$/,"",$i);
if(index($i,",")!=0){ $i="\047"$i"\047" } r=(r!="")? r","$i : $i
} print r }' text.txt
输出:
59280d9b95385c78b73252e4,1100000041,PROD GROUP,N,1053,800-319-03,PP,SEATS,PP SER,'^AY,EECH, NG-C',200699,S-INTV,90000,orcl,1495797136138,2017-05-26 11:12:16.138Z,tool,2017-05-26 11:12:16.138Z,tool,PP FAMILY,750,PP SERIES PRODUCTS
-F':|, *"'
- 字段分隔符
for(i=2;i<=NF;i+=2)
- 遍历所有甚至字段
gsub(/^ *([^(]+\()?|"|\)$/,"",$i)
- 替换/删除过多的实例名称,例如ObjectId(
和双引号"
答案 1 :(得分:0)
你的一些字段值嵌入了逗号,所以这很可能是徒劳的,但是......
#! /bin/sed -rf
s/\s*"[^"]+"\s*:\s*\w+\s*\("([^"]*)"\)\s*/\1/g
s/\s*"[^"]+"\s*:\s*\w+\s*\(([^)]*)\)\s*/\1/g
s/\s*"[^"]+"\s*:\s*"([^"]*)"\s*/\1/g
s/\s*"[^"]+"\s*:\s*([0-9]+)\s*/\1/g