Question

$searchTerm = isset($_GET['txtSearch']) ? $_GET['txtSearch'] : '';
$searchTerm = strtolower($searchTerm);
$searchTerm = strip_tags($searchTerm);
$searchTerm = trim($searchTerm," "); 

$keywords = explode(" ",$searchTerm); // break down search term into individual keywords

$in = join(',', array_fill(0, count($keywords), '?'));
$select = <<<SQL
    SELECT * 
    FROM m_products
    WHERE product_title IN ($in);
SQL;
$statement = $con->prepare($select);
$statement->bind_param(str_repeat('s', count($$keywords)), ...$keywords); //s = string, d = double, i = integer
$statement->execute();

我从上面的代码中收到以下错误：

注意：
中的数组到字符串转换
注意：未定义的变量：
中的数组
警告：mysqli_stmt :: bind_param（）：无效的类型或
中指定的类型

如何解决此错误？

Answer 1

正如我在上面的评论中所说：

self.numbersStackViewTopMarginConstriant.constant = self.view.frame.size.height
UIView.animate(withDuration: 0.5, animations: {

            self.view.layoutIfNeeded()

        }) { (Bool) in

在$statement->bind_param(str_repeat('s', count($$keywords)), ...$keywords); //s = string, d = double, i = integer中有一个双$ $$删除一个$，应该解决错误。

使用mysqli bind_param错误“使用字符串转换字符串”

1 个答案: