如何只从字符串数组中获取所需的元素

Question

我有一个字符串数组，我只想要用户需要的元素。字符串数组如下：

 const char* string2[]={"•-","-•••", "-•-•","-••", "•", "••-•","--•","••••","••","•---","-•-","•-••",
                       "--","-•","---","•-•","--•-","•-•","•••","-","••-","•••-","•--","-••-",
                       "-•--","--••","•----","••---","•••--","••••-","•••••","-••••","--•••","---••",
                       "----•","-----"," "};

我创建了一个逻辑，我可以从中获取用户所需的字符串数组，但是我无法获得正确的输出。问题是例如我输入Hello，我得到的数字如下：[8 5 12 12 15]

现在我希望我的输出为string2 [8]：••，string2 [5]：•• - •等等。

我需要做些什么更改才能让它在此工作？

for(a[i]=0;a[i]<length;a[i++]){
        printf("%s\t",string2[i]);
    }

我试图让它发挥作用，但我无法取悦。

Answer 1

您可能需要以下内容：

for(int i = 0; i < length; i++)
    printf("%s\t", string2[a[i]]);