Question

我是 Oracle SQL 的新手，希望有人可以帮助我。

我有一个使用Listagg组合多个列/值的Select语句。 SQL作业的输出是一个文本文件，然后手动导入Excel。

我的查询本身有效，但我希望在生成的文本文件中强制使用回车符/新行，这样我的Listagg中的所有数据都不会出现在一行中。

我在聚合的列之间尝试了|| ' chr(10) column name: ' ||和|| ' CHAR(10) column name: ' ||但是在导入文本文件时 Excel无法将其识别为新行（在同一单元格内）并将其显示为文本，并且全部在同一行中。

有人能告诉我如何实现这一目标吗？

更新

我的查询（第一部分）：

SELECT a.SHIPPER_ID , LISTAGG ( 'Item No.: ' || ducsi.ITEM_NUMBER || ' chr(10)Article: ' || c.ARTICLE || ' chr(10)Quantity: ' || b.QUANTITY || ' chr(10)chr(10)' ) WITHIN GROUP (ORDER BY b.SHIPMENT_ID) /* ... */

当前输出：

Item No.: 123 chr(10)Article: Item A chr(10)Quantity: 10 ...

预期输出：

Item No.: 123 Article: Item A Quantity: 10 ...

非常感谢，麦克

Answer 1

您获取chr(10)作为文字的原因是因为，您将其包含在文字字符串中。你必须将它连接到文本字符串，例如'some text'||chr(10)||'some more text'

但是，我认为listagg并不是你应该在这里使用的，特别是因为你可以在结果字符串中输出多少限制。

相反，我认为你是在UNPIVOT之后，例如：

WITH sample_data AS (SELECT 1 shipper_id, 10 item_number, 'abc' article, 100 quantity FROM dual UNION ALL
                     SELECT 2 shipper_id, 20 item_number, 'efg' article, 200 quantity FROM dual UNION ALL
                     SELECT 3 shipper_id, 30 item_number, 'hij' article, 300 quantity FROM dual)
-- end of mimicking a table called sample_data with data in it
-- see SQL below:
SELECT CASE WHEN row_number() OVER (PARTITION BY shid
                                    ORDER BY CASE WHEN column_name = 'Item No.:' THEN 1
                                                  WHEN column_name = 'Article:' THEN 2
                                                  WHEN column_name = 'Quantity:' THEN 3
                                                  ELSE 4
                                             END) = 1
                 THEN shid
       END shipper_id,
       column_name||' '||vals results
FROM   (SELECT shipper_id shid,
               to_char(item_number) "Item No.:",
               article "Article:",
               to_char(quantity) "Quantity:"
        FROM   sample_data)
UNPIVOT (vals FOR column_name IN ("Item No.:", "Article:", "Quantity:"))
ORDER BY shid,
         CASE WHEN column_name = 'Item No.:' THEN 1
              WHEN column_name = 'Article:' THEN 2
              WHEN column_name = 'Quantity:' THEN 3
              ELSE 4
         END;

SHIPPER_ID RESULTS
---------- --------------------------------------------------
         1 Item No.: 10
           Article: abc
           Quantity: 100
         2 Item No.: 20
           Article: efg
           Quantity: 200
         3 Item No.: 30
           Article: hij
           Quantity: 300

此处使用row_number（）分析函数以确保仅为第一行显示shipper_id。

case when column_name = ...案例表达式用于确保以正确的顺序（item_number，文章和数量）输出列（在row_number（）分析函数和整体结果中）。

ETA：如果每个出货单ID可以有多个item_numbers，那么需要对上述查询进行一些调整：

WITH sample_data AS (SELECT 1 shipper_id, 10 item_number, 'abc' article, 100 quantity FROM dual UNION ALL
                     SELECT 1 shipper_id, 11 item_number, 'xyz' article, 110 quantity FROM dual UNION ALL
                     SELECT 2 shipper_id, 20 item_number, 'efg' article, 200 quantity FROM dual UNION ALL
                     SELECT 3 shipper_id, 30 item_number, 'hij' article, 300 quantity FROM dual)
-- end of mimicking a table called sample_data with data in it
-- see SQL below:
SELECT CASE WHEN row_number() OVER (PARTITION BY shid ORDER BY CASE WHEN column_name = 'Item No.:' THEN 1 WHEN column_name = 'Article:' THEN 2 WHEN column_name = 'Quantity:' THEN 3 ELSE 4 END) = 1
                 THEN shid
       END shipper_id,
       column_name||' '||vals results
FROM   (SELECT shipper_id shid,
               item_number,
               to_char(item_number) "Item No.:",
               article "Article:",
               to_char(quantity) "Quantity:"
        FROM   sample_data)
UNPIVOT (vals FOR column_name IN ("Item No.:", "Article:", "Quantity:"))
ORDER BY shid,
         item_number,
         CASE WHEN column_name = 'Item No.:' THEN 1 WHEN column_name = 'Article:' THEN 2 WHEN column_name = 'Quantity:' THEN 3 ELSE 4 END;

SHIPPER_ID RESULTS
---------- --------------------------------------------------
         1 Item No.: 10
           Article: abc
           Quantity: 100
           Item No.: 11
           Article: xyz
           Quantity: 110
         2 Item No.: 20
           Article: efg
           Quantity: 200
         3 Item No.: 30
           Article: hij
           Quantity: 300

Oracle SQL：在输出文本文件

1 个答案: