我在这里遇到一些问题，我有两张桌子
1st Table: user
[user_id,name]
(1,"Shelby")
(2,"barray")
(3,"Obor")
2nd Table: payment_transaction
[payment_id,payment_date,payment_user_id (this refer to user id from table user), payment_amount]
(1,"2017-06-09 16:48:37",1,20)
我想像这个透视示例一样输出它：
name | Jan | Feb | Mar | Apr | May | June | July .. Dec | <br>
Shelby | 0 | 0 | 0 | 0 | 0 | 20 | ... 0 |<br>
barray | 0 | 0 | 0 | 0 | 0 | 0 | ... 0 |<br>
Obor | 0 | 0 | 0 | 0 | 0 | 0 | ... 0 |<br>
我设法正确使用这个sql：
SELECT pt.name,
SUM(case when month(s.payment_date) = 1 THEN s.payment_amount ELSE 0 END)
'Jan',
SUM(case when month(s.payment_date) = 2 THEN s.payment_amount ELSE 0 END)
'Feb',
SUM(case when month(s.payment_date) = 3 THEN s.payment_amount ELSE 0 END)
'Mar',
SUM(case when month(s.payment_date) = 4 THEN s.payment_amount ELSE 0 END)
'Apr',
SUM(case when month(s.payment_date) = 5 THEN s.payment_amount ELSE 0 END)
'May',
SUM(case when month(s.payment_date) = 6 THEN s.payment_amount ELSE 0 END)
'Jun',
SUM(case when month(s.payment_date) = 7 THEN s.payment_amount ELSE 0 END)
'Jul',
SUM(case when month(s.payment_date) = 8 THEN s.payment_amount ELSE 0 END)
'Aug',
SUM(case when month(s.payment_date) = 9 THEN s.payment_amount ELSE 0 END)
'Sep',
SUM(case when month(s.payment_date) = 10 THEN s.payment_amount ELSE 0 END)
'Oct',
SUM(case when month(s.payment_date) = 11 THEN s.payment_amount ELSE 0 END)
'Nov',
SUM(case when month(s.payment_date) = 12 THEN s.payment_amount ELSE 0 END)
'Dec'
from user pt left join payment_transactions on pt.user_id = s.payment_user_id group by pt.name
但是，我想尽快将Where子句用于在特定日期获取数据
WHERE YEAR(s.payment_date)='2017'
它只输出：
name | Jan | Feb | Mar | Apr | May | June | July .. Dec | <br>
Shelby | 0 | 0 | 0 | 0 | 0 | 20 | ... 0 |<br>
另外两个名字没有出来。
我可能知道在一年中检索数据库的错误在哪里吗？
谢谢你！