比较并减去记录2表

Question

我有2个表（每个表有两个相同的结构） 我用波纹管代码得到两个表的总和。 现在我想查找上个月的记录总和和当月的总和，并比较它们。 如果前一个月的总和大于当前月份的总和，则选择。如果没有，则不选择

Table 1                                        Table 2<br>
StudentId=1  Score=50 Date =2017/01/01      StudentId= 1 Score=100 Date =2017/01/01<br>
StudentId=1  Score=20 Date =2017/02/01      StudentId= 1 Score=10 Date =2017/02/01<br>
StudentId=2  Score=60 Date =2017/01/01      StudentId= 2 Score=100 Date =2017/01/01<br>
StudentId=2  Score=540 Date =2017/02/01     StudentId= 2 Score=100 Date =2017/02/01<br>

当前结果：

StudentId       HighScoreUser<br>
1               180<br>
2               800<br>
---------------------------------<br>

我想要的结果：

StudentId   Prev Month(2017/01/01)  Current Month(2017/02/01)<br>
1           150                     30<br>
2           160                     640<br>

1 - ＆gt; 150> 30 - ＆gt;真的吗？ - ＆GT;是的，所以必须选择

2 - ＆gt; 160> 640 - ＆gt;是吗？ - ＆GT;不，所以一定不能选择

结果（选定值）= StudentId，（Sum prev Month - Sum Current Month）

<br>`CREATE PROCEDURE SelectTopMonth
    @Date1  NVARCHAR(12),
    @Date2  NVARCHAR(12)
AS
    SELECT StudentId, ISNULL(SUM(Score),0) As HighScoreUser
FROM (SELECT StudentId, Score FROM tbl_ActPoint     WHERE Date >= @Date1    AND     Date <= @Date2
      UNION ALL
      SELECT StudentId, Score FROM tbl_EvaPoint     WHERE Date >= @Date1    AND     Date <= @Date2
     ) as T 
GROUP BY  StudentId ORDER BY HighScoreUser DESC
RETURN 0`

Answer 1

我认为您希望看到如下数据：

Select StudentId, [2017/01/01] as [Prev Month(2017/01/01)],
                  [2017/02/01] as [Current Month(2017/02/01)] from (
    Select * from t1
    Union all
    Select * from t2
    ) a
    pivot (sum([Score]) for [Date] in ([2017/01/01],[2017/02/01]) ) p
    Where [2017/01/01] > [2017/02/01]

Answer 2

您可以使用SQL Server的主要分析功能来获得结果。

<强> TABLE1

create table table1 
(
  studentid integer,
  score integer,
  date date
);

insert into table1 values(1,50,'2017/01/01'); 
insert into table1 values(1,20,'2017/02/01');
insert into table1 values(2,60,'2017/01/01');
insert into table1 values(2,540,'2017/02/01');  

<强> TABLE2

create table table2
(
  studentid integer,
  score integer,
  date date
);
insert into table2 values(1,100,'2017/01/01'); 
insert into table2 values(1,10,'2017/02/01');
insert into table2 values(2,100,'2017/01/01');
insert into table2 values(2,100,'2017/02/01');  

查询：

with data  as (
select table1.studentid , (table1.score + table2.score) as pre_score, table1.date,
lead((table1.score + table2.score),1) over(partition by table1.studentid order by table1.studentid,table1.date) 
as cur_score
from table1 join table2 
on table1.studentid = table2.studentid 
and table1.date = table2.date
)
select * from data
where cur_score is not null 
and pre_score > cur_score

根据您的评论添加此条件＆＃34;和pre_score＆gt; cur_score＆＃34 ;.