Question

我有给定格式的数据：

Id  | Total_Inv_Amount  | Total_Rec_Inv_Amount  | Invoice_No    Invoice_Amont   | Payment_Outstanding   | Refund_Outstanding   
1   | 25000 | 22000 | 5 | 15000 | 0 | 0   
1   | 25000 | 22000 | 6 | 10000 | 0 | 0   
2   | 45000 | 48000 | 10| 25000 | 0 | 0   
2   | 45000 | 48000 | 15| 20000 | 0 | 0

预期结果......

Id  | Total_Inv_Amount  | Total_Rec_Inv_Amount  | Invoice_No    Invoice_Amont   | Payment_Outstanding   | Refund_Outstanding   
1   | 25000 | 22000 | 5 | 15000 | 0     | 0   
1   | 25000 | 22000 | 6 | 10000 | 3000  | 0   
2   | 45000 | 48000 | 10| 25000 | 0     | 0   
2   | 45000 | 48000 | 15| 20000 | 0     | 2000

计算： -
   发票号5＆amp; 6总金额为：15000 + 10000 = 25000
   收到的总金额为：22000

现在在现场Payment_Outstanding发票号码是0
   因为total_invoice_amt＆gt;发票5金额    22000> 15000比付款未付款为0    剩余金额为22000-15000 = 7000

现在从下一张发票中扣除此金额，金额为10000

10000-7000 = 3000这是未付款

现在请帮我解决如何在查询中计算

Answer 1

递归查询非常适合获取运行值。第一个cte添加了一个由递归部分使用的rownumber。在递归部分中进行计算。在最终结果中，低于0的值不会显示。

Declare @myTable table (Id int, Total_Inv_Amount float,
    Total_Rec_Inv_Amount float,Invoice_No int,   
    Invoice_Amount float, Payment_Outstanding float, 
    Refund_Outstanding float)

insert into @myTable values
(1   , 25000 , 22000 , 5 , 15000 , 0 , 0  ), 
(1   , 25000 , 22000 , 6 , 10000 , 0 , 0  ), 
(2   , 45000 , 48000 , 10, 25000 , 0 , 0  ), 
(2   , 45000 , 48000 , 15, 20000 , 0 , 0  )

;with first_cte as
(
    select *, ROW_NUMBER() over (partition by id order by invoice_no) rn
    from @myTable
)
, result_rte as
(
    select m.Id, m.Total_Inv_Amount,m.Total_Rec_Inv_Amount,
        m.Invoice_No,   m.Invoice_Amount, m.Payment_Outstanding, 
        m.Refund_Outstanding, m.rn, invoice_Amount TotalAmount
    from first_cte m
    where rn = 1
    union all
    select m.Id, m.Total_Inv_Amount,m.Total_Rec_Inv_Amount,
        m.Invoice_No,   m.Invoice_Amount,  
        r.TotalAmount + m.Invoice_Amount - m.Total_Rec_Inv_Amount , 
        m.Total_Rec_Inv_Amount - (r.TotalAmount + m.Invoice_Amount), 
        m.rn, r.TotalAmount + m.Invoice_Amount
    from result_rte r
    join first_cte m on r.id = m.id and r.rn+1 = m.rn
)

select Id, Total_Inv_Amount,Total_Rec_Inv_Amount,Invoice_No,   Invoice_Amount, 
    case when Payment_Outstanding > 0 then Payment_Outstanding else 0 end Payment_Outstanding  , 
    case when Refund_Outstanding > 0 then Refund_Outstanding else 0 end Refund_Outstanding
from result_rte order by invoice_no

如何计算SQL Server查询中的运行余额？

1 个答案: