User32的ShowWindow没有按预期运行

时间:2009-01-14 20:19:44

标签: c# .net system.diagnostics user32

我使用User32的ShowWindow方法隐藏用户的窗口(cmd.exe)(主要是为了防止它们关闭它)。当用户打开表单时,进程启动并隐藏,然后当表单关闭时,进程被终止。但是,当表单再次打开时,它不会隐藏窗口(有时不是第一次)有人可以帮助我吗?

    [DllImport("User32")]
    private static extern int ShowWindow(int hwnd, int nCmdShow);   //this will allow me to hide a window

    public ConsoleForm(Process p) {
        this.p = p;
        p.Start();
        ShowWindow((int)p.MainWindowHandle, 0);   //0 means to hide the window. See User32.ShowWindow documentation SW_HIDE

        this.inStream = p.StandardInput;
        this.outStream = p.StandardOutput;
        this.errorStream = p.StandardError;

        InitializeComponent();

        wr = new watcherReader(watchProc);
        wr.BeginInvoke(this.outStream, this.txtOut, null, null);
        wr.BeginInvoke(this.errorStream, this.txtOut2, null, null);
    }

    private delegate void watcherReader(StreamReader sr, RichTextBox rtb);
    private void watchProc(StreamReader sr, RichTextBox rtb) {
        string line = sr.ReadLine();
        while (line != null && !stop && !p.WaitForExit(0)) {
            //Console.WriteLine(line);
            line = stripColors(line);
            rtb.Text += line + "\n";

            line = sr.ReadLine();
        }
    }

    public void start(string[] folders, string serverPath) {

        this.inStream.WriteLine("chdir C:\\cygwin\\bin");
        //this.inStream.WriteLine("bash --login -i");
        this.inStream.WriteLine("");
    }

    private void ConsoleForm_FormClosed(object sender, FormClosedEventArgs e) {
        this.stop = true;
        try {
            this.p.Kill();
            this.p.CloseMainWindow();
        } catch (InvalidOperationException) {
            return;
        }
    }

2 个答案:

答案 0 :(得分:4)

这会更容易:

public ConsoleForm(Process p) {
        this.p = p;
        p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
        p.StartInfo.CreateNoWindow = true;
        p.Start();

        this.inStream = p.StandardInput;
        this.outStream = p.StandardOutput;
        this.errorStream = p.StandardError;

        InitializeComponent();

        wr = new watcherReader(watchProc);
        wr.BeginInvoke(this.outStream, this.txtOut, null, null);
        wr.BeginInvoke(this.errorStream, this.txtOut2, null, null);
    }

答案 1 :(得分:0)

您是否检查过p.MainWindowHandle是否为有效句柄?它至少必须是非零的。请尝试拨打IsWindow进行确认。

在检查MainWindowHandle之前,

MSDN suggests致电WaitForInputIdle;您可能在新进程创建窗口之前访问该属性。不过,该属性本质上是不稳定的,因为进程实际上没有“主”窗口的概念。所有窗户都得到平等对待。 .Net框架只是将第一个窗口指定为主窗口,但该过程本身不需要考虑这种方式。

另外,您是否考虑过最初只是隐藏进程,而不是启动它然后隐藏在事实之后?设置流程的StartInfo属性as Scotty2012 demonstrates