我要做的是从网址下载一些图片然后将其上传到WordPress帖子,我的表单如下:
<form method="post" id="upload">
<?php foreach($data as $row): ?>
<label>File Name</label>
<input type="text" id="filename_<?php echo $row->id;?>" name="data[<?php echo $row->id;?>][filename]" value="<?php echo $file_name;?>" />
<label>Title</label>
<input type="text" id="title_<?php echo $row->id;?>" name="data[<?php echo $row->id;?>][title]" value="<?php echo $title;?>" />
<?php endforeach;?>
<button name="act" value="savepost">Save</button>
</form>
<!-- showing result here -->
<div id="result"></div>
那么,当点击“保存”按钮时...操作将调用 function prc_upload()
function prc_upload() {
$posts = $_POST['data'];
foreach ($posts as $post) {
$filename = $post['filename'];
$title = $post['title'];
// Process uplaoding here
// Process uplaoding here
// Process uplaoding here
if (!$fileSaved) {
$result = $filename.' Can not saved !!';
} else {
$result = filename' Saved Succesfuly!!';
}
}
如何在单击“保存”按钮时使用jquery显示响应结果。
答案 0 :(得分:0)
将你的img追加到html
像
$($post).each(function(){
$('#placeIDwhereYouWantToShowImg').append('<img src='+this.imgsrc+' class="if any"/>')
})
答案 1 :(得分:0)
确保您的表单具有enctype =“multipart / form-data”属性。
$new_post = wp_insert_post($post_array);
if (!function_exists('wp_generate_attachment_metadata')){
require_once(ABSPATH . "wp-admin" . '/includes/image.php');
require_once(ABSPATH . "wp-admin" . '/includes/file.php');
require_once(ABSPATH . "wp-admin" . '/includes/media.php');
}
if ($_FILES) {
foreach ($_FILES as $file => $array) {
if ($_FILES[$file]['error'] !== UPLOAD_ERR_OK) {
return "upload error : " . $_FILES[$file]['error'];
}
$attach_id = media_handle_upload( $file, $new_post );
}
}
if ($attach_id > 0){
update_post_meta($new_post,'_thumbnail_id',$attach_id);
}