sprintf字符串manupulation在loadrunner中无法正常工作

Question

我正在构建一个这样的queryString：

#include <stdio.h>

int main()
{
    char filters[300];
    char logicalAnd[5] = " and ";
    char orderNumberFilter[55];
    char punchOrderFilter[50];
    char jobsiteFilter[50];
    char frenteFilter[50];
    char statusFilter[23];

    char orderNumber[] = "pedidos";
    char punchOrder[] = "123456789";
    char jobsite[] = "65119415";
    char frente[] = "65119415";
    char status[] = "B";

    sprintf(orderNumberFilter, "OrderNum eq '%s'", orderNumber);
    sprintf(punchOrderFilter, "PurchOrder eq '%s'", punchOrder);
    sprintf(jobsiteFilter, "Jobsite eq '%s'", jobsite);
    sprintf(frenteFilter, "Frente eq '%s'", frente);
    sprintf(statusFilter, "Status eq '%s'", status);

    sprintf(filters, "%s%s%s%s%s%s", "&$filter=", orderNumberFilter, logicalAnd, punchOrderFilter, logicalAnd, jobsiteFilter);
    printf(filters);

    return 0;
}

我使用在线编译器获得此输出：

&$filter=OrderNum eq 'pedidos' and PurchOrder eq '123456789' and Jobsite eq '65119415'

但是当我使用lr_output_message("filters: %s", filters);在loadrunner中尝试相同的代码来显示结果时，这就是我得到的：

&$filter=OrderNum eq 'pedidos' and &$filter=OrderNum eq 'pedidos'PurchOrder eq '123456789' and &$filter=OrderNum eq 'pedidos' and &$filter=OrderNum eq 'pedidos'PurchOrder eq '123456789'Lº¯L•¯L‹Jobsite eq '65119415'

我还尝试了一个使用strcpy看到的基本示例：

sprintf(orderNumberFilter, "OrderNum eq '%s'", orderNumber);
sprintf(punchOrderFilter, "PurchOrder eq '%s'", punchOrder);
sprintf(jobsiteFilter, "Jobsite eq '%s'", jobsite);
sprintf(frenteFilter, "Frente eq '%s'", frente);
sprintf(statusFilter, "Status eq '%s'", status);

strcpy(filters, "&$filter=");
strcpy(filters, orderNumberFilter);
strcpy(filters, logicalAnd);
strcpy(filters, punchOrderFilter);
strcpy(filters, logicalAnd);
strcpy(filters, jobsiteFilter);

lr_output_message("filters: %s", filters);

这是输出：

Jobsite eq '65119415'

所以...什么时候继续加载runnner？

*替换strgspy for strcat作为@Some程序员dude sugested

char filters[300];
char logicalAnd[5] = " and ";
char orderNumberFilter[55];
char punchOrderFilter[50];
char jobsiteFilter[50];
char frenteFilter[50];
char statusFilter[23];

char orderNumber[] = "pedidos";
char punchOrder[] = "123456789";
char jobsite[] = "65119415";
char frente[] = "65119415";
char status[] = "B";

sprintf(orderNumberFilter, "OrderNum eq '%s'", orderNumber);
sprintf(punchOrderFilter, "PurchOrder eq '%s'", punchOrder);
sprintf(jobsiteFilter, "Jobsite eq '%s'", jobsite);
sprintf(frenteFilter, "Frente eq '%s'", frente);
sprintf(statusFilter, "Status eq '%s'", status);

strcpy(filters, "&$filter=");
strcat(filters, orderNumberFilter);
strcat(filters, logicalAnd);
strcat(filters, punchOrderFilter);
strcat(filters, logicalAnd);
strcat(filters, jobsiteFilter);

这是输出：

&$filter=OrderNum eq 'pedidos' and OrderNum eq 'pedidos'PurchOrder eq '123456789' and OrderNum eq 'pedidos'Jobsite eq '65119415'

它更接近但却是混乱的。

Answer 1

中有未终止的字符串

char logicalAnd[5] = " and ";

如果你写

char logicalAnd[] = " and ";

与其他字符串文字一样，编译器将包含'\0'终结符。但是你限制了数组长度，在这种情况下编译器不包括终结符，或发出警告。

实际上，当你传递你认为是“字符串”的行为时，行为是未定义的，但不是，对于strcpy和strcat等字符串处理函数。