d3.js scale-chromatic未按预期工作

时间:2017-06-08 16:48:07

标签: javascript json d3.js

我有json数据:

{
  "nodes": 
  [{"id": "Michael Scott"}, 
   {"id": "Jim Halpert"}, 
   {"id": "Pam Beasley"}
  ], 
  "links": 
  [{"source": "Michael Scott", "target": "Jim Halpert", "value": 50}, 
   {"source": "Michael Scott", "target": "Pam Beasley", "value": 25}
  ]
}

我有代码:

<!DOCTYPE html>
<meta charset="utf-8">
<style>

.links line {
  stroke: #aaa;
}

.nodes circle {
  pointer-events: all;
  stroke: none;
  stroke-width: 40px;
}

</style>
<svg width="960" height="600"></svg>
<script src="https://d3js.org/d3.v4.min.js"></script>
<script src="https://d3js.org/d3-scale-chromatic.v1.min.js"></script>
<script>

var svg = d3.select("svg"),
    width = +svg.attr("width"),
    height = +svg.attr("height");

var simulation = d3.forceSimulation()
    .force("link", d3.forceLink().id(function(d) { return d.id; }))
    .force("charge", d3.forceManyBody())
    .force("center", d3.forceCenter(width / 2, height / 2));

d3.json("data.json", function(error, graph) {
  if (error) throw error;

  var link = svg.append("g")
      .attr("class", "links")
      .selectAll("line")
      .data(graph.links)
      .enter().append("line");

  var color = d3.scaleSequential(d3.interpolateBlues);

  var node = svg.append("g")
      .attr("class", "nodes")
      .selectAll("circle")
      .data(graph.nodes)
      .enter().append("circle")
      .attr("r", 2.5)
      .style("fill", function(d) { return color(d.value); })
      .call(d3.drag()
          .on("start", dragstarted)
          .on("drag", dragged)
          .on("end", dragended));

  node.append("title")
      .text(function(d) { return d.id; });

  simulation
      .nodes(graph.nodes)
      .on("tick", ticked);

  simulation.force("link")
      .links(graph.links);

  function ticked() {
    link
        .attr("x1", function(d) { return d.source.x; })
        .attr("y1", function(d) { return d.source.y; })
        .attr("x2", function(d) { return d.target.x; })
        .attr("y2", function(d) { return d.target.y; });

    node
        .attr("cx", function(d) { return d.x; })
        .attr("cy", function(d) { return d.y; });
  }
});

function dragstarted(d) {
  if (!d3.event.active) simulation.alphaTarget(0.3).restart();
  d.fx = d.x;
  d.fy = d.y;
}

function dragged(d) {
  d.fx = d3.event.x;
  d.fy = d3.event.y;
}

function dragended(d) {
  if (!d3.event.active) simulation.alphaTarget(0);
  d.fx = null;
  d.fy = null;
}

</script>

这会产生一个力导向图,而不会使节点着色。为什么var color = d3.scaleSequential(d3.interpolateBlues);线与.style("fill", function(d) { return color(d.value); })线相交的节点没有变色?是因为value附加到链接而不是节点?如果是这样,我将如何更改代码以显示链接的色标?

感谢您有任何见解!

0 个答案:

没有答案