Question

`list1 = ["Arizona","Atlanta","Baltimore","Buffalo","Carolina","Chicago",
"Cincinnati","Cleveland","Dallas","Denver","Detroit","Green Bay","Houston",
"Indianapolis","Jacksonville","Kansas City","L.A. Chargers","L.A. Rams",
    "Miami","Minnesota","New England","New Orleans","NY Giants","NY Jets",
    "Oakland","Philadelphia","Pittsburgh","San Francisco","Seattle",
    "Tampa Bay","Tennessee","Washington"]
a = "New Orleans at Oakland"
k = a.find("at")
print (k)
for n in range(0,31):
#    b = list1[n]
#    print(b[0:k-1]+"  "+a[0:k-1])
    idx = a.find(list1[n], 0, k-1)
    if idx > 0:
        print(n)
        break
print ("awa team at index" + str(n+1))
for n in range(0,31):
    idx = a.find(list1[n], k+2, len(a))
    if idx > 0:
       print(n)
       break
print ("hom team at index" + str(n+1))`

我刚刚在2天前启动了python，我无法让它完全运行。程序正确找到第二个for循环中的团队，但是在第一个for循环中找不到团队。我放入了注释掉的语句，以查看字符串是否以某种方式被截断，但它们是正确的。谁能告诉我这里有什么问题？

Answer 1

没有必要暴力搜索。 Python拥有可以满足您需求的方法。

list1 = ["Arizona", "Atlanta", "Baltimore", "Buffalo", "Carolina", "Chicago",
"Cincinnati", "Cleveland", "Dallas", "Denver", "Detroit", "Green Bay", "Houston",
"Indianapolis", "Jacksonville", "Kansas City", "L.A. Chargers", "L.A. Rams",
"Miami", "Minnesota", "New England", "New Orleans", "NY Giants", "NY Jets",
"Oakland", "Philadelphia", "Pittsburgh", "San Francisco", "Seattle",
"Tampa Bay", "Tennessee", "Washington"]

a = "New Orleans at Oakland"

# Create a list of the teams involved in the game
teams = a.split(" at ")

# Iterate through the teams involved in the game
for team in teams:
    # The index() method returns the lowest index in list that obj appears
    index = list1.index(team)
    # If the the team was found then index is valid
    if index:
        print(index)
        print(list1[index])

Answer 2

如果您只想拥有索引，则可以使用.index（），而不必使用＆＃34;循环＆＃34;

示例代码：

list1 = ["Arizona","Atlanta","Baltimore","Buffalo","Carolina","Chicago",
"Cincinnati","Cleveland","Dallas","Denver","Detroit","Green Bay","Houston",
"Indianapolis","Jacksonville","Kansas City","L.A. Chargers","L.A. Rams",
    "Miami","Minnesota","New England","New Orleans","NY Giants","NY Jets",
    "Oakland","Philadelphia","Pittsburgh","San Francisco","Seattle",
    "Tampa Bay","Tennessee","Washington"]

a = "New Orleans at Oakland"

a = a.split(' at ')

idx_home_team = list1.index(a[0])
idx_away_team = list1.index(a[1])

print(idx_home_team, idx_away_team)

python substring（切片）比较并不总是有效

2 个答案: