这是我的img标记：
<img src="https://myserver.com/image?w=667&h=375 667w"
srcset="https://myserver.com/image?w=1366&h=1024 1366w 1x,
https://myserver.com/image?w=1366&h=1024&dpr=2 1366w 2x,
https://myserver.com/image?w=1366&h=1024&dpr=3 1366w 3x,
https://myserver.com/image?w=1024&h=768 1024w 1x,
https://myserver.com/image?w=1024&h=768&dpr=2 1024w 2x,
https://myserver.com/image?w=1024&h=768&dpr=3 1024w 3x,
https://myserver.com/image?w=800&h=480 800w 1x,
https://myserver.com/image?w=800&h=480&dpr=2 800w 2x,
https://myserver.com/image?w=800&h=480&dpr=3 800w 3x" sizes="100%">
我正在使用imgix，它根据dpr查询参数以正确的像素密度返回图像。以上似乎不起作用，图像不会以正确的大小呈现。我没有使用正确的格式吗？
答案 0 :(得分：3)
您无法在x属性中混合w和srcset个描述符。
我不知道imgix，但我想?w=800&h=480&dpr=2会返回尺寸为1600x960像素的图片。 https://myserver.com/image?w=800&h=480&dpr=2和https://myserver.com/image?w=1600&h=960&dpr=1是同一张图片吗？
如果图像在每个可见尺寸上始终相同（相同内容和相同的宽高比），则应定义所需的可见/ CSS尺寸（取决于您的设计，例如800,1200和1600像素）并写入这样：
<img
src="https://myserver.com/image?w=800&h=400"
srcset="https://myserver.com/image?w=800&h=400 800w,
https://myserver.com/image?w=1200&h=600 1200w,
https://myserver.com/image?w=1600&h=800 1600w,
https://myserver.com/image?w=2000&h=1000 2000w,
https://myserver.com/image?w=2400&h=1200 2400w,
https://myserver.com/image?w=2800&h=1400 2800w,
https://myserver.com/image?w=3200&h=1600 3200w"
sizes="100vw">
浏览器将下载?w=2400&h=1200图像以进行多种配置：