我在这个项目工作了3天，如果你可以帮助我，我无法弄清楚我在哪里做错了我非常感谢你的帮助。我正在努力创造一个tic tac toe game.When我正在运行游戏，如果玩家X或O赢了一条消息，会弹出说X或O获胜。但是如果非用户赢了一条消息，则会弹出并说没有赢家。赢家的弹出窗口工作得很好，但没有人赢的弹出不起作用。如果你可以帮助我解决它，你真的在为我的一天做好准备。
public class MainActivity extends AppCompatActivity {
MediaPlayer mediaPlayer;
int activePlayer = 0; // for x player
int[] gameState ={2,2,2,2,2,2,2,2,2}; // 2 means unplayed.
int[][] winningLocation ={{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}};
boolean gameover =false;
public void gameLogic(View view){
ImageView tappedView =(ImageView) view;
int tappedLocation = Integer.parseInt(view.getTag().toString());
if(gameState[tappedLocation]==2 && !gameover) {
gameState[tappedLocation]=activePlayer;
tappedView.setTranslationY(-3000f);
if (activePlayer == 0) {
tappedView.setImageResource(R.drawable.x);
activePlayer = 1;
} else if (activePlayer == 1) {
tappedView.setImageResource(R.drawable.o);
activePlayer = 0;
}
tappedView.animate().translationYBy(3000f).setDuration(500);
}
String mesg ="";
for(int[]winningPostion :winningLocation){
if(gameState[winningPostion[0]] == gameState [winningPostion[1]]
&& gameState[winningPostion[1]]== gameState [winningPostion[2]]
&& gameState[winningPostion[0]]!=2){
if (activePlayer ==0)
mesg = "O is the winner!";
if(activePlayer==1)
mesg = "X is the winner!";
else
gameover=true;
mesg="there is no winner ";
LinearLayout winnerLayout =(LinearLayout)findViewById (R.id.winnerLayout);
winnerLayout.setVisibility(View .VISIBLE);
TextView winnermesg = (TextView) findViewById(R.id.editText);
winnermesg.setText(mesg);
gameover=true;
}
}
}
// a method that let the players play again
public void playagain(View view){
LinearLayout winnerLayout = (LinearLayout) findViewById(R.id.winnerLayout);
winnerLayout.setVisibility(View.INVISIBLE);
gameover=false;
activePlayer=0;
for (int i =0; i < gameState.length;i++)
gameState[i]=2;
GridLayout gridlayout = (GridLayout) findViewById(R.id.gridlayout);
for(int i =0 ; i < gridlayout.getChildCount(); i++)
((ImageView)gridlayout.getChildAt(i)).setImageResource(0);
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// to play the song
mediaPlayer = MediaPlayer.create(getApplicationContext(),R.raw.song);
mediaPlayer.start();
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
// to show and hide the playing again button
LinearLayout winnerLayout = ( LinearLayout) findViewById(R.id.winnerLayout);
winnerLayout.setVisibility(View.INVISIBLE);
FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
}
});
}
// pause and play the song when the user leaving annd returning the game
@Override
protected void onPause(){
super.onPause();
mediaPlayer.stop();
mediaPlayer.release();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
答案 0 :(得分：1)
创建一个检查数组的函数：
int[] gameState ={2,2,2,2,2,2,2,2,2};
如果所有人都与2不同，并且没有一名球员获胜，则意味着它的平局。
编辑：
使用此功能，可以判断您的arr是否包含item：
public static boolean my_contains(int[] arr, int item) {
for (int n : arr) {
if (item == n) {
return true;
}
}
return false;
}
然后做：
//Check winning position
for(int[]winningPostion :winningLocation){
//If there is a winning position
if(gameState[winningPostion[0]] == gameState [winningPostion[1]]
&& gameState[winningPostion[1]]== gameState[winningPostion[2]]
&& gameState[winningPostion[0]]!=2){
//Look for the winner
if (activePlayer ==0)
mesg = "O is the winner!";
if(activePlayer==1)
mesg = "X is the winner!";
LinearLayout winnerLayout =(LinearLayout)findViewById (R.id.winnerLayout);
winnerLayout.setVisibility(View .VISIBLE);
TextView winnermesg = (TextView) findViewById(R.id.editText);
winnermesg.setText(mesg);
gameover=true;
}
}
//Here, all winning position have been checked, and gameover is still false
//Check if all X and O have been placed
if(!my_contains(gameSate, 2) && !gameover){
//If so, and gameover is false, then its a tie.
gameover=true;
mesg="there is no winner ";
//README : this may be the wrong layout, its up to you to change it to the good one, but it should pop your message
LinearLayout winnerLayout =(LinearLayout)findViewById (R.id.winnerLayout);
winnerLayout.setVisibility(View .VISIBLE);
TextView winnermesg = (TextView) findViewById(R.id.editText);
winnermesg.setText(mesg);
}
答案 1 :(得分：0)
用大括号{}
封闭块else {
gameover=true;
mesg="there is no winner ";
}
答案 2 :(得分：0)
可能因为这段代码而无法正常工作
if (activePlayer ==0)
mesg = "O is the winner!";
if(activePlayer==1)
mesg = "X is the winner!";
else
gameover=true;
mesg="there is no winner ";
尝试使用花括号，无论如何都是最佳实践。像这样：
if (activePlayer ==0){
mesg = "O is the winner!";
}else if(activePlayer==1){
mesg = "X is the winner!";
}else{
gameover=true;
mesg="there is no winner ";
}
答案 3 :(得分：0)
目前，您不会跟踪任何获胜者，因为您的if()会检查已播放的相同符号行。
没有赢家意味着没有相同符号的行，但董事会已满。您可以计算非格子（在数组中计数2）或每次播放符号时递增计数器。一旦你格子9但没有获胜线，那么它就是平局。
if(gameState[winningPostion[0]] == gameState[winningPostion[1]]
&& gameState[winningPostion[1]] == gameState[winningPostion[2]]
&& gameState[winningPostion[0]] !=2 ) {
//somebody has scored a line, but who?
} else if (haveWePlayed9()) {
//no winner
}
答案 4 :(得分：0)
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