Question

我想动态更改json属性名并序列化对象。

这是我的两个不同实体的json

对于客户

{
  "userName": "66666",
  "password": "test1234",  
  "customersList": [
    {
      "address": "Test Stree2",
      "customerNumber": "US01-000281",
      "city": ""

    }
  ]
}

联系

{
  "userName": "66666",
  "password": "test1234",  
  "contactList": [
    {
      "address": "Test stree1",
      "contactNumber": "US01-000281",
      "city": ""

    }
  ]
}

并且持有此数据的模型如下

public class URequest<T>
    {

        [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
        public string userName { get; set; }

        [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
        public string password { get; set; }    

       [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
        public IList<T> requestList { get; set; }

    }

上面的代码requestList中的

可能包含contacts或customer的列表，但在发送时我想将requestList json属性名称更改为相应的实体名称，即{{ 1}}它将是customer，而对于customerList，序列化后它将是contact。

Answer 1

使用ContentResolver我解决了问题

这是代码

public class UserRequestResolver : DefaultContractResolver
    {

        private string propertyName;

        public UserRequestResolver()
        {

        }
        public UserRequestResolver(String name)
        {

            propertyName = name;
        }
         public new static readonly UserRequestResolver Instance = new UserRequestResolver();
        protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization)
         {
             JsonProperty property = base.CreateProperty(member, memberSerialization);

             if ( property.PropertyName == "requestList")
            {
                property.PropertyName = propertyName;

            }

            return property;
        }
    }

一旦可以在构造函数中传递特定的属性名称。

JsonSerializerSettings settings = new JsonSerializerSettings();
            settings.ContractResolver = new UserRequestResolver("contactList");

Answer 2

您可以创建自定义JsonConverter。

Using custom JsonConverter in order to alter the serialization of the portion of an object

实施例

public class Customer
{
    public string Name { get; set; }
}

public class Client
{
    public string Name { get; set; }
}

public class URequest<T>
{

    [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
    public string userName { get; set; }

    [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
    public string password { get; set; }

    [JsonIgnore]
    public IList<T> requestList { get; set; }

}

public class URequestConverter<T> : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return (objectType == typeof(URequest<T>));
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var objectType = value.GetType().GetGenericArguments()[0];
        URequest<T> typedValue = (URequest<T>) value;

        JObject containerObj = JObject.FromObject(value);

        containerObj.Add($"{objectType.Name.ToLower()}List", JToken.FromObject(typedValue.requestList));
        containerObj.WriteTo(writer);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

您可以像这样使用

    [TestMethod]
    public void TestMethod1()
    {
        URequest<Customer> request = new URequest<Customer>();
        request.password = "test";
        request.userName = "user";
        request.requestList = new List<Customer>();

        request.requestList.Add(new Customer() { Name = "customer" });

        JsonSerializerSettings settings = new JsonSerializerSettings();
        settings.Formatting = Formatting.Indented;
        settings.Converters.Add(new URequestConverter<Customer>());

        Console.WriteLine(JsonConvert.SerializeObject(request, settings));
    }

动态更改json属性名称并序列化

2 个答案: