Question

如果有多列IN子句，如何为hibernate SQL查询设置参数？

例如，SQL查询应该如下生成：

SELECT * FROM TABLE TA WHERE (TA.COLUMN1 , TA.COLUMN2) IN ((C1v, C2v), (C1v, C2v), .....);

我看到这可以通过Spring jdbcTemplate来实现here，但我想在Hibernate SQL Query中使用它。

我尝试了以下方案，但它们都不适合我：

String sql = "SELECT * FROM TABLE TA WHERE (TA.COLUMN1 , TA.COLUMN2) IN (:ids)";
// 1. List of BigDecimal array's
List<BigDecimal[]> ids = new ArrayList<>();
BigDecimal[] bd1 = {new BigDecimal(100119401), new BigDecimal(2)};
BigDecimal[] bd2 = {new BigDecimal(100119000), new BigDecimal(1)};
ids.add(bd1);
ids.add(bd2);

Query query = session.createSQLQuery(sql);
query.setParameterList("ids", ids);

// 2. List of Object arrays
List<Object []> ids = new ArrayList<>();
Object [] bd1 = {new BigDecimal(100119401), new BigDecimal(2)};
Object [] bd2 = {new BigDecimal(100119000), new BigDecimal(1)};
ids.add(bd1);
ids.add(bd2);

Query query = session.createSQLQuery(sql);
query.setParameterList("ids", ids);

// 3. List of inner lists with ids
List<BigDecimal> ob1 = new ArrayList<BigDecimal>();
ob1.add(new BigDecimal(100119401));ob1.add(new BigDecimal(2));
List<BigDecimal> ob2 = new ArrayList<BigDecimal>();
ob2.add(new BigDecimal(100119401));ob2.add(new BigDecimal(2));
List<List<BigDecimal>> ids = new ArrayList<List<BigDecimal>>(); 
ids.add(ob1);ids.add(ob2);

Query query = session.createSQLQuery(sql);
query.setParameterList("ids", ids);

在所有情况下，我得到“ORA-00920：无效的关系运营商”错误。

例外：

Caused by: java.sql.SQLSyntaxErrorException: ORA-00920: invalid relational operator

    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:450)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:399)
    at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:1017)
    at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:655)
    at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:249)
    at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:566)
    at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:215)
    at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:58)
    at oracle.jdbc.driver.T4CPreparedStatement.executeForDescribe(T4CPreparedStatement.java:776)
    at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:897)
    at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1034)
    at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3820)
    at oracle.jdbc.driver.OraclePreparedStatement.executeQuery(OraclePreparedStatement.java:3867)
    at oracle.jdbc.driver.OraclePreparedStatementWrapper.executeQuery(OraclePreparedStatementWrapper.java:1502)
    at org.apache.tomcat.dbcp.dbcp.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:96)
    at org.apache.tomcat.dbcp.dbcp.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:96)
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:82)
    ... 141 more

Answer 1

这样的事情应该有效：

String sql = "SELECT * FROM TABLE TA WHERE CONCAT(TA.COLUMN1, '|', TA.COLUMN2) IN (:values)";
List<String> values = new ArrayList<>();
values.add("100119401|2");
values.add("100119000|1");

// ...

Query query = session.createSQLQuery(sql);
query.setParameterList("values", values);

NB：确保使用的分隔符|不在您的数据中

使用带有hibernate SQL查询的多列的参数化IN子句

1 个答案: