Question

1.从具有不同日期的同一个表中获取值

 <?php 
    $date= date("Y-m-d");;
    $prev_date = date('Y-m-d', strtotime($date .' -1 day'));
    $result_yest=mysql_query("SELECT isp,sum(sent) AS `sent_yest` FROM red_global WHERE status_date='$prev_date' and sent > 0 group by 1",$link1);
    $data_yest = array(); // create a variable to hold the information
    while (($row_yest = mysql_fetch_array($result_yest, MYSQL_ASSOC)) !== false){
      $data_yest[] = $row_yest; // add the row in to the results (data) array
    }
    print_r($data_yest); 
    $result_today=mysql_query("SELECT isp,sum(sent) AS `sent_today` FROM red_global WHERE status_date='$date' and sent > 0 group by 1",$link1);
    $data_today = array(); // create a variable to hold the information
    while (($row_today = mysql_fetch_array($result_today, MYSQL_ASSOC)) !== false){
      $data_today[] = $row_today; // add the row in to the results (data) array
    }
    print_r($data_today); 
    exit;
?>

2.Array导致一个数组包含昨天发送的计数，另一个数组包含今天发送的计数两个数组都有共同的isp

Array ( 
  [0] => Array ( [isp] => aol [sent_yest] => 46838 ) 
  [1] => Array ( [isp] => gmail [sent_yest] => 33015 ) 
  [2] => Array ( [isp] => juno [sent_yest] => 93544 ) 
  [3] => Array ( [isp] => roadrunner [sent_yest] => 6181 ) 
  [4] => Array ( [isp] => yahoo [sent_yest] => 71444 ) 
)

Array ( 
  [0] => Array ( [isp] => aol [sent_today] => 14135 ) 
  [1] => Array ( [isp] => att [sent_today] => 624 ) 
  [2] => Array ( [isp] => gmail [sent_today] => 21263 ) 
  [3] => Array ( [isp] => juno [sent_today] => 74934 ) 
  [4] => Array ( [isp] => roadrunner [sent_today] => 939 ) 
  [5] => Array ( [isp] => yahoo [sent_today] => 22059 ) 
)

现在我需要一个像这个isp名称的结果，昨天的发送次数，今天的发送次数

[isp, sent_yest, sent_today],
[aol, 46838,  14135],
[att, 0,  624],
[gmail, 33015,  21263],

任何人都帮我解决这个问题..提前致谢

Answer 1

如下所示： -

$final_array = array();

if(count($arr1)>=count($arr2)){
  foreach ($arr1 as $arr){
      $key='';
      foreach ($arr2 as $ar2){
         if($arr['isp'] == $ar2['isp']){
            $final_array[$arr['isp']] = array($arr['isp'],$arr['sent_yest'],$ar2['sent_today']);
            $key ='';break;
         }else{
             $key = $arr['isp'];
         }
      }
      if($key!==''){
            $final_array[$key] = array($arr['isp'],$arr['sent_yest'],0);
            $key ='';
      }
  }
}

if(count($arr2)>count($arr1)){
   foreach ($arr2 as $ar2){
       $key='';
      foreach ($arr1 as $arr){
         if($ar2['isp'] == $arr['isp']){
            $final_array[$ar2['isp']] = array($ar2['isp'],$arr['sent_yest'],$ar2['sent_today']);
             $key ='';break;
         }else{
             $key = $ar2['isp'];
         }
      }
      if($key!==''){
            $final_array[$key] = array($ar2['isp'],0,$ar2['sent_today']);
            $key ='';
      }
   }
}

echo "<pre/>";print_r($final_array);

输出： - https://eval.in/814625

Answer 2

如果可能的话，我会避免使用foreach，因为这会导致代码难以理解。使用数组操作，它可以如下所示：

// First we merge the two arrays
$merged = array_merge($data_yest, $data_today);

// Then format it
$final = array_reduce($merged, function($final, $item) {

    // Initialize for each isp if it's not present
    // This way we avoid overwriting previous data and have a default value 0
    if (! isset($final[ $item['isp'] ])) {
        $final[ $item['isp'] ] = [
            'sent_yest' => 0,
            'sent_today' => 0,
        ];
    }

    // And if one of the days is present, we add it
    if (isset($item['sent_yest'])) {
        $final[ $item['isp'] ][ 'sent_yest' ] = $item['sent_yest'];
    }
    if (isset($item['sent_today'])) {
        $final[ $item['isp'] ][ 'sent_today' ] = $item['sent_today'];
    }

    // Then return the modified array
    return $final;
}, []);

print_r($final);
exit;

结果如下所示：

Array
(
    [aol] => Array
        (
            [sent_yest] => 46838
            [sent_today] => 14135
        )

    [gmail] => Array
        (
            [sent_yest] => 33015
            [sent_today] => 21263
        )

    [juno] => Array
        (
            [sent_yest] => 93544
            [sent_today] => 74934
        )

    [roadrunner] => Array
        (
            [sent_yest] => 6181
            [sent_today] => 939
        )

    [yahoo] => Array
        (
            [sent_yest] => 71444
            [sent_today] => 22059
        )

    [att] => Array
        (
            [sent_yest] => 0
            [sent_today] => 624
        )

)

如何通过公共值将2个数组值组合成单个数组

2 个答案: