import java.io.FileOutputStream;
import java.io.IOException;
import java.nio.file.*;
import java.nio.file.attribute.BasicFileAttributes;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipCompress {
public static void compress(String dirPath) {
final Path sourceDir = Paths.get(dirPath);
String zipFileName = dirPath.concat(".zip");
try {
final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFileName));
Files.walkFileTree(sourceDir, new SimpleFileVisitor<Path>() {
@Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attributes) {
try {
Path targetFile = sourceDir.relativize(file);
outputStream.putNextEntry(new ZipEntry(targetFile.toString()));
byte[] bytes = Files.readAllBytes(file);
outputStream.write(bytes, 0, bytes.length);
outputStream.closeEntry();
} catch (IOException e) {
e.printStackTrace();
}
return FileVisitResult.CONTINUE;
}
});
outputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
页面上有20个按钮排成一排。如何单击每个按钮以提醒其索引。 Ex点击button1将提示1
答案 0 :(得分:2)
<script>
for(var i = 0; i < 20; i++) {
document.write("<button onclick='alert("+(i + 1)+")'>Button " + (i + 1) +"</button> <br/> <br/>");
}
</script>
&#13;
您好,上面的简单方法,它适合我。请运行代码段。
问候 潮
答案 1 :(得分:1)
ty<pe="button"
应该是type="button"
的拼写错误。除此之外,你可以直接为内联函数编写警报,因为你的函数myFunction
实际上没有做任何有效的工作。
var index = 21;
var Buttons = $('#Buttons');
for (var i = 1; i <index; i++) {
Buttons.append('<input type="button" onclick="alert('+i+')" id="button" ' + i + '" value="Button' + i + '"/>');
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<div id="Buttons"></div>
答案 2 :(得分:0)
enter code here
var totalButton = 20;
var buttonsDiv = document.getElementById('buttons');
for (var i = 1; i <totalButton; i++) {
var button = document.createElement("input");
button.type = "button";
button.value= "Button "+i;
button.id = i;
button.onclick = function(event){
alert(event.target.id);
}
buttonsDiv.append(button);
}
<div id="buttons"></div>