Question

请检查我的代码。我有2个字段用于验证电子邮件

一个

if ($email == NULL) {
            $error['email'] = "email is missing";
        }

另一个是

if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
            $error['emailfilter'] = "email is Invalid";
    }

但我的问题是当电子邮件字段为空/空时。我发现那2个交战是显示的。 “电子邮件丢失”＆amp; “电子邮件无效”;我只希望展示一个战争。例如，如果电子邮件提交为空白/空白。它只会显示“电子邮件丢失”没有显示“电子邮件无效”，当电子邮件无效时它将显示“电子邮件无效”。以下是我的完整代码。

<?php
    if (isset($_POST['contact'])) {

        $warning = array();
        $firstname = $_POST['firstname'];
        $lastname = $_POST['lastname'];
        $email = $_POST['email'];
        $msg = $_POST['message'];
        $to = "asifurrahaman124@gmail.com";
        $sub = "you got a msg";
        $headers = "from: $email";

        if ($firstname == NULL) {
            $error['fname'] = "firstname is missing";
        }
        if($lastname == NULL){
            $error['lname'] = "Last name is missing";
        }
        if ($email == NULL) {
            $error['email'] = "email is missing";
        }

        if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
            $error['emailfilter'] = "email is Invalid";
        }

        if ($msg == NULL) {
            $error['msg'] = "message is required";
        }
        if (count( $error ) == 0) {
            mail($to, $sub, $msg, $headers);

            $success = "Message Submited";
        }
    }


?>

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>conatact</title>
    <link rel="stylesheet" href="style.css">
</head>
<body>
    <form action="" method="POST">
        <input type="text" name="firstname" Placeholder="First Name"><br />
        <p class="error"><?php if (isset($error['fname'])) {
            echo $error['fname'];
        }?></p>
        <input type="text" name="lastname" Placeholder="Last Name"><br />
        <p class="error"><?php if (isset($error['lname'])) {
            echo $error['lname'];
        }?></p>
        <input type="email" name="email" Placeholder="Email"><br />
        <p class="error"><?php if (isset($error['email'])) {
            echo $error['email'];
        }?></p>
        <p class="error"><?php if (isset($error['emailfilter'])) {
            echo $error['emailfilter'];
        }?></p>
        <textarea name="message"  cols="30" rows="10"></textarea><br />
        <p class="error"><?php if (isset($error['msg'])) {
            echo $error['msg'];
        }?></p>

        <input type="password" name="password" Placeholder="Password"><br />
        <input type="submit" value="send" name="contact">

    </form>
    <h2 class="error"><?php if (isset($success)) {
            echo $success;
        }?></h2>
</body>
</html>

Answer 1

您希望使用elseif，只有在第一个条件不匹配时才会触发。

if ($email == NULL) {
    $error['email'] = "email is missing";
} elseif (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
    $error['emailfilter'] = "email is Invalid";
}

这将检查第一个条件，他们是否有电子邮件，如果没有填写$error['email']，如果电子邮件有值，那么它将执行电子邮件上的filter_var以检查这是有效的。

不确定如何解决有关FILTER_VALIDATE_EMAIL的此问题

1 个答案: